如何在Node.js中访问URL查询参数?

时间:2019-05-08 19:43:22

标签: node.js typescript

如何使用typescript访问nodejs中的url查询参数? 我尝试过的在这里?

    /**
 * My Server app
 */
import * as Http from "http";
import * as url from "url";
import { HttpServer } from "./HttpServer";
import { TaxCalculator } from "./TaxCalculator";
export interface myReq extends Http.IncomingMessage {
  amount: string;
  rate: string;
}
/**
 * MyServer class
 * Create MyServer from HttpServer
 */
class MyServer extends HttpServer {
  /**
   * Create a new NodeServer object
   * @param port Port number of the server
   * @param name Name of the server
   */
  constructor(port: number, name: string) {
    super(port, name);
  }
  /**
   * Handle the Request in request nad populate the response to response
   * @param request Incoming Request
   * @param response Outgoing Response
   */
  onRequest(request: myReq, response: Http.ServerResponse): void {
    response.writeHead(200, {"Content-Type": "text/plain"});
// const { amount, rate } = url.parse(request.url, true).query;
    const query = url.parse(request.url, true).query;
    const tc = new TaxCalculator();
    const tax = tc.calculate(query.amount, query.rate);
    response.end(JSON.stringify(tax));
  }
}

// Create a server instance
const port = 8080;
new MyServer(port, "Test server");

错误是'string |类型的参数字符串[]'不可分配给类型为'n的参数 琥珀色”。

1 个答案:

答案 0 :(得分:1)

在路由处理中间件内部,有路由器回调的req, res, next参数。您正在寻找req.query。[您的查询参数]。

对于打字稿,您需要创建一个扩展express.Request的接口,并在其中添加查询参数。然后将该类型分配给您的请求参数。

interface myReq extends express.Request {
    query: {
        [Whatever params you have in your route]: string;
    }
}

router.get("/", (req: myReq, res, next) => {
  ...
})

如果还没有,您还必须在文件中导入快递