Question

我有一堂课很好。现在，我想计算一些东西并将其记录下来，但这不应该影响性能，因此，我想创建一个线程并认为线程应该实现这一点。但是从来没有做过线程。因此，思考实现可运行和运行类。不知道我怎么能做到这一点。

class Test implements ServiceA, Runnable
{

    private final ServiceA one;
    private final ServiceA two;
    Test(ServiceA one, ServiceA two)
       {
        this.one = one;
        this.two= two;
    }

    @override
    public objectA calculate(TInput input)
    {
        objectA objAOne = one.Find(input);
        // First I just had "return one.calculate(input)";
        // Now I want to create a thread and that should do 2 things.
        // 1. call "two.calculate(input)" -- App Shouldnt wait for the response of this
        // 2. log this (which i know).
        //How can i create a thread here that can help me achieve this 

        return objAOne ;
    }

    @Override
    public void run()
    {       
    }
}

有人可以帮我吗？

Answer 1

我知道在乞讨中很难理解多线程。这是一个简单的示例，可能会为您提供指导

public class MyTest {
    static class MyWorker implements Runnable {
        public String result = "not calculated yet";
        private String params;

        public MyWorker(String params) {
            this.params = params;
        }

        @Override
        public void run() {
            // calculate here
            this.result = "Result of calculation for " + this.params;
        }
    }

    public static void main(String[] args) throws InterruptedException {
        MyWorker w1 = new MyWorker("One");
        MyWorker w2 = new MyWorker("Two");

        new Thread(w1).start();
        new Thread(w2).start();

        System.out.println("0 w1 result: " + w1.result);
        System.out.println("1 w2 result: " + w2.result);

        Thread.sleep(1000);

        System.out.println("2 w1 result: " + w1.result);
        System.out.println("3 w2 result: " + w2.result);
    }
}

可能的输出：

0 w1 result: not calculated yet
1 w2 result: not calculated yet
2 w1 result: Result of calculation for One
3 w2 result: Result of calculation for Two

Process finished with exit code 0

在现有应用程序中添加简单的多线程功能

1 个答案: