如何解决XSLT 3.0地图问题？

时间：2019-05-08 15:48:51

标签： xslt-3.0

我将一个XML文件作为输入，其中包含员工数据和映射值，即工作族ID和工作族名。因此，当员工具有匹配的工作族ID时，我们将替换Worker_Data中的工作族名称，而Worker_Data中的其余元素相同。因此，我使用了身份匹配，然后在需要替换值的地方调用了元素。但这给了我工作族名称的空白。

我尝试了下面的XSLT代码来创建地图，并为Job Family ID匹配调用了相同的名称。这只是给我空白。不清楚我缺少什么。如果你们中的任何一个可以给我提示发生了什么问题，那对我真的很有帮助。

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:map="http://www.w3.org/2005/xpath-functions/map" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:wd="urn:com.workday/bsvc" exclude-result-prefixes="xs" version="3.0">

    <xsl:mode streamable="no" on-no-match="shallow-skip" use- accumulators="JobFamilyLookup CurrentLookupValue" />

    <xsl:output method="xml" />

    <xsl:accumulator name="CurrentLookupValue" as="xs:string" initial- value="''" streamable="no">
        <xsl:accumulator-rule match="wd:JobFamilyID/text()" select="string()" />
    </xsl:accumulator>

    <xsl:accumulator name="JobFamilyLookup" as="map(xs:string,xs:string)" initial-value="map{}" streamable="no">
        <xsl:accumulator-rule match="wd:JobFamilyName/text()" select="map:put($value, accumulator- 
    before('CurrentLookupValue'),string(.))" />
    </xsl:accumulator>

    <xsl:strip-space elements="*" />

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()" />
        </xsl:copy>
    </xsl:template>

    <xsl:template match="wd:Job_Family_ID">
        <xsl:copy>
            <xsl:value-of select="accumulator-before('JobFamilyLookup') ( 
        normalize-space( wd:Job_Family_ID ) )" />
        </xsl:copy>
    </xsl:template>

    <xsl:template match="wd:JobFamilyGroupDetails">

    </xsl:template>
</xsl:stylesheet>

输入：

<?xml version="1.0" encoding="UTF-8"?>
<wd:test xmlns:wd="urn:com.workday/bsvc">
<wd:Worker_Data>
    <wd:EmpID>50001</wd:EmpID>
    <wd:Job_Title>Global Talent Director</wd:Job_Title>
    <wd:Job_Family_ID>TAL_TALENT_ACQUISITION</wd:Job_Family_ID>
</wd:Worker_Data>
<wd:Worker_Data>
    <wd:EmpID>50000</wd:EmpID>
    <wd:Job_Title>Executive Assistant</wd:Job_Title>
    <wd:Job_Family_ID>ADMIN_EXECUTIVE_ASSISTANT</wd:Job_Family_ID>
</wd:Worker_Data>
<wd:JobFamilyGroupDetails>
    <wd:JobFamilyDetails>
        <wd:JobFamilyID>ADMIN_EXECUTIVE_ASSISTANT</wd:JobFamilyID>
        <wd:JobFamilyName>ADMIN - Executive Assistant</wd:JobFamilyName>
    </wd:JobFamilyDetails>
    <wd:JobFamilyDetails>
        <wd:JobFamilyID>TAL_TALENT_ACQUISITION</wd:JobFamilyID>
        <wd:JobFamilyName>TAL - Talent Acquisition</wd:JobFamilyName>
    </wd:JobFamilyDetails>
   </wd:JobFamilyGroupDetails>
</wd:test>

预期输出：

<?xml version="1.0" encoding="UTF-8"?>
<wd:test xmlns:wd="urn:com.workday/bsvc">
<wd:Worker_Data>
    <wd:EmpID>50001</wd:EmpID>
    <wd:Job_Title>Global Talent Director</wd:Job_Title>
    <wd:Job_Family_ID>TAL - Talent Acquisition</wd:Job_Family_ID>
</wd:Worker_Data>
<wd:Worker_Data>
    <wd:EmpID>50000</wd:EmpID>
    <wd:Job_Title>Executive Assistant</wd:Job_Title>
    <wd:Job_Family_ID>ADMIN - Executive Assistant</wd:Job_Family_ID>
</wd:Worker_Data>
</wd:test>

1 个答案:

答案 0 :(得分：1)

我只会使用一个键：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xpath-default-namespace="urn:com.workday/bsvc"
    exclude-result-prefixes="#all"
    expand-text="yes"
    version="3.0">

  <xsl:key name="details" match="JobFamilyDetails" use="JobFamilyID"/>

  <xsl:mode on-no-match="shallow-copy"/>

  <xsl:template match="Worker_Data/Job_Family_ID[key('details', .)]">
      <xsl:copy>{key('details', .)/JobFamilyName}</xsl:copy>
  </xsl:template>

  <xsl:template match="JobFamilyGroupDetails"/>

</xsl:stylesheet>

https://xsltfiddle.liberty-development.net/ncdD7mJ

关于您对使用流和累加器的请求，因为流工作仅转发解决该问题的唯一方法，那就是将相关的工作数据存储在一系列地图中，然后在您捕获地图中的明细数据之后尝试将其用作输出相关元素的worker数据映射序列中每个项目的模板参数：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:map="http://www.w3.org/2005/xpath-functions/map"
    xmlns:wd="urn:com.workday/bsvc"
    xpath-default-namespace="urn:com.workday/bsvc"
    exclude-result-prefixes="#all"
    version="3.0">

    <xsl:mode on-no-match="shallow-skip" streamable="yes" use-accumulators="#all"/>

    <xsl:output method="xml" indent="yes"/>

    <xsl:accumulator name="current-id" as="xs:string?" initial-value="()" streamable="yes">
        <xsl:accumulator-rule match="JobFamilyDetails/JobFamilyID/text()"
            select="string()"/>
    </xsl:accumulator>

    <xsl:accumulator name="details" as="map(xs:string, xs:string)" initial-value="map{}" streamable="yes">
        <xsl:accumulator-rule match="JobFamilyDetails/JobFamilyName/text()"
            select="map:put($value, accumulator-before('current-id'), string())"/>
    </xsl:accumulator>

    <xsl:accumulator name="workers" as="map(xs:string, xs:string)*" initial-value="()" streamable="yes">
        <xsl:accumulator-rule match="Worker_Data" select="$value, map { }"/>
        <xsl:accumulator-rule match="Worker_Data/EmpID/text()" 
            select="let $wmap := $value[last()]
            return ($value[position() lt last()], map:put($wmap, 'id', string()))"/>
        <xsl:accumulator-rule match="Worker_Data/Job_Title/text()" 
            select="let $wmap := $value[last()]
            return ($value[position() lt last()], map:put($wmap, 'title', string()))"/>
        <xsl:accumulator-rule match="Worker_Data/Job_Family_ID/text()" 
            select="let $wmap := $value[last()]
            return ($value[position() lt last()], map:put($wmap, 'jfid', string()))"/>
    </xsl:accumulator>

    <xsl:template match="/*">
        <xsl:copy>
            <xsl:apply-templates/>
            <xsl:apply-templates select="accumulator-after('workers')" mode="output">
                <xsl:with-param name="details" select="accumulator-after('details')"/>
            </xsl:apply-templates>
        </xsl:copy>
    </xsl:template>

    <xsl:template match=".[. instance of map(*)]" mode="output" expand-text="yes">
        <xsl:param name="details"/>
        <wd:Worker_Data>
            <wd:EmpID>{?id}</wd:EmpID>
            <wd:Job_Title>{?title}</wd:Job_Title>
            <wd:Job_Family_ID>{$details(?jfid)}</wd:Job_Family_ID>
        </wd:Worker_Data>      
    </xsl:template>

</xsl:stylesheet>

https://xsltfiddle.liberty-development.net/pPzifpL/2

在内存使用方面是否表现良好，我尚未测试。

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