Scala案例类匹配是否可以使用命名参数?

时间:2019-05-08 15:28:30

标签: scala pattern-matching wildcard case-class

假设存在一个Scala案例类Point

case class Point(x: Int, y: Int)

一个人可以使用通配符进行匹配:

val p = new Point(1,2)
val inRightHalfPlane = p match {
  case Point(x, _) if x>0 => true
  case _ => false
}

但是,如果成员数量增加,则将需要使用更多的通配符_

case class Point(
  x0: Int,
  x1: Int,
  x2: Int,
  x3: Int,
  x4: Int,
)


val flag = p match {
  case Point(x,_,_,_,_,) if x>0 => true
  ......
}

是否有类似以下代码的语法糖?

val flag = p match {
  case Point(x0=x) if x>0 => true
  ......
}

1 个答案:

答案 0 :(得分:7)

您可以定义自定义unapply

  case class Point(
                    x0: Int,
                    x1: Int,
                    x2: Int,
                    x3: Int,
                    x4: Int,
                  )

  object PositiveFirst {
    def unapply(p: Point): Option[Int] = if (p.x0 > 0) Some(p.x0) else None
  }

  val p: Point = ???

  val flag = p match {
    case PositiveFirst(x) => true
//      ......
  }