Question

如果我动态创建的列表不为空，则需要引发异常，之后是此https://github.com/hashicorp/terraform/issues/15469，我在下面创建了代码，如果列表不为空，它应该失败并显示错误，如您所见，列表是根据null_resource构建列表，它总是引发断言：

resource "null_resource" "empty_string" {
  count = "10"
  triggers = {
    value  = ""
  }
}

locals {
  compacted_list_length = "${length(compact(null_resource.empty_string.*.triggers.value))}"
}

resource "null_resource" "is_array_empty" {
  count = "${local.compacted_list_length}"
  "Lsit is not empty" = true
}


output "compacted_list_length" {
  value = "${local.compacted_list_length}"
}

如果您要评论以下内容，输出将显示0

resource "null_resource" "is_array_empty" {
      count = "${local.compacted_list_length}"
      "Lsit is not empty" = true
}

如果将本地人设置为：

locals {
  compacted_list_length = 0
}

即使此代码也可以正常工作：

locals {
  empty_list = ["", "", ""]
  compacted_list_length = "${length(compact(local.empty_list))}"
}

resource "null_resource" "is_array_empty" {
  count = "${local.compacted_list_length}"
  "Lsit is not empty" = true
}

output "compacted_list_length" {
  value = "${local.compacted_list_length}"
}

我的错误在哪里？

Answer 1

此断言解决方法不适用于动态值，因为它在验证阶段起作用。在此阶段，Terraform不会计算动态值。

此声明变通办法很好地验证了变量值，如documentation中两个示例中所建议的。请注意，在两种情况下，计数值仅基于变量值。这些值在验证阶段可用，而不是动态值。

resource "null_resource" "is_environment_name_valid" {
  count = "${contains(var.environment_list, var.env) == true ? 0 : 1}"
  "ERROR: The env value can only be: dev, qa or prod" = true
}

resource "null_resource" "is_array_length_correct" {
  count = "${length(var.array1) == length(var.array2) ? 0 : 1}"
  "array1 and array2 must be the same length" = true
}

Terraform v0.11.xx“ null_resource”并非始终用作断言

1 个答案: