Question

我有一个这样的JSON对象：

var x = {
zy5EwY0caL3rPk4PXyX3: { name: 'Bob', completedDate: '2019-03-27T01:56:27.589Z'},
zy4HsKbHYZKtZNBMHdxu: { name: 'Tom', completedDate: '2019-04-10T01:56:27.589Z'},
zy0VPwMY51ksZaTFFIxL: { name: 'Jim', completedDate: '2019-05-01T01:56:27.589Z'},
zw6Xmv5PiNE4dmC19q2p: { name: 'Joe', completedDate: '2019-05-02T01:56:27.589Z'}
}

我想在节点脚本中运行一些JavaScript来过滤并仅返回过去10天内完成数据的对象，然后返回以下内容。

var filteredData = {
zy0VPwMY51ksZaTFFIxL: { name: 'Jim', completedDate: '2019-05-01T01:56:27.589Z'},
zw6Xmv5PiNE4dmC19q2p: { name: 'Joe', completedDate: '2019-05-02T01:56:27.589Z'}
}

我遇到了问题，因为数据是嵌套的。我已经尝试在下划线中使用.where函数，但是我不知道让它检查嵌套元素的语法。

有一种简单的方法来获取我想要的东西吗？

Answer 1

由于源数据不是数组，因此不能使用Array.filter。

所以您可以做的是使用Object.entries进行迭代，然后将其放置到另一个对象中。

下面是一个简单的例子。

const x = {
zy5EwY0caL3rPk4PXyX3: { name: 'Bob', completedDate: '2019-03-27T01:56:27.589Z'},
zy4HsKbHYZKtZNBMHdxu: { name: 'Tom', completedDate: '2019-04-10T01:56:27.589Z'},
zy0VPwMY51ksZaTFFIxL: { name: 'Jim', completedDate: '2019-05-01T01:56:27.589Z'},
zw6Xmv5PiNE4dmC19q2p: { name: 'Joe', completedDate: '2019-05-02T01:56:27.589Z'}
};

const day = 1000 * 60 * 60 * 24;
//const now = Date.now();
//let's set a date time, so snippet will continue to work
//in the future, but Date.now() would be use
//for current time
const now = new Date("2019-05-08T14:29:27.589Z");

const ret = {};
for (const [k, v] of Object.entries(x)) {
  const tmc = new Date(v.completedDate);
  const diff = Math.abs(tmc.getTime() - now);
  if (diff < 10 * day) ret[k] = v;
}

console.log(ret);

过滤嵌套的JSON

1 个答案: