Question

我正在尝试创建一个计划的云函数，该函数使用api调用中的值更新文档字段。但是我在日志中遇到了上面提到的错误，我应该返回一个诺言（据我所知）

任何帮助都将得到

api调用返回此json：

{ "alarm": "false" }

我的代码：

import * as functions from 'firebase-functions';
import * as admin from 'firebase-admin';
import * as rp from 'request-promise';

admin.initializeApp()

export const scheduledAlarmUpdate = functions.pubsub.schedule('every 30 minutes').onRun((context) => {

    const docRef = admin.firestore().collection('alarms').doc('stuttgart');
    const username = 'bitfactory';
    const pass = '...';

    const options = {
        url: 'https://api.bitfactory.io/fineparticlesalarm/',
        auth: {
            user: username,
            password: pass
        },
        method: 'GET',
        json: true
    }

    return rp(options).then(data => {
        console.log(data.alarm)

        docRef.set({
            alarm: data.alarm
        })
        .catch(err => {
            console.log(err);
        });
    })
});

Answer 1

您需要返回set()方法返回的promise，如下所示：

export const scheduledAlarmUpdate = functions.pubsub
  .schedule('every 30 minutes')
  .onRun(context => {
    const docRef = admin
      .firestore()
      .collection('alarms')
      .doc('stuttgart');
    const username = 'bitfactory';
    const pass = '...';

    const options = {
      url: 'https://api.bitfactory.io/fineparticlesalarm/',
      auth: {
        user: username,
        password: pass
      },
      method: 'GET',
      json: true
    };

    return rp(options)
      .then(data => {
        console.log(data.alarm);

        return docRef.set({  // ->>> here return
          alarm: data.alarm
        });
      })
      .catch(err => {
        console.log(err);
      });
  });

计划的云函数错误：函数返回的值未定义，预期的承诺或价值

1 个答案: