Question

我正在使用firebase_messaging 收到通知时，我将显示警报对话框。下面是我的代码。

showNotification(BuildContext context) {
    _firebaseMessaging.configure(
      onMessage: (Map<String, dynamic> message) async {
        print('on message $message');
        _showPushNotificationDialog(message['notification']['title'],
            message['notification']['body'], context);
      },
      onResume: (Map<String, dynamic> message) async {
        print('on resume $message');
        _showPushNotificationDialog(
            message['data']['title'], message['data']['body'], context);
      },
      onLaunch: (Map<String, dynamic> message) async {
        print('on launch $message');
        _showPushNotificationDialog(
            message['data']['title'], message['data']['body'], context);
      },
    );
  }

每次调用 onMessage ， onResume 和 onLaunch 方法时，将在_showPushNotificationDialog方法处调用。

面临的问题，例如当我的应用程序处于后台或终止模式时，通知将出现，并轻按通知托盘，一切正常。但是，当我转到另一页并一直返回到上一个_firebaseMessaging.configure(....方法调用时，该方法调用具有数据，因此每次我的警报对话框都弹出。

那么如何清除通知托盘中单击的通知？

Answer 1

尝试在initState而非自定义方法中配置firebaseMessaging。那应该工作：）

Answer 2

我也有这个问题。我有以下解决方法：我所做的就是用静态布尔和静态方法创建一个类：

Int

然后我在路由小部件的初始化中调用了此方法：

class MessagingWidget {

  static bool _isConfigured = false;


  static void configuringFirebase(User currentUser, BuildContext context){
      

      final FirebaseMessaging _firebaseMessaging = FirebaseMessaging();
      if (!_isConfigured) {
      _firebaseMessaging.configure(
      onMessage: (Map<String, dynamic> message) async {
        print("onMessage: $message");
        final notification = message['notification'];
      },
      onLaunch: (Map<String, dynamic> message) async {
        print("onLaunch: $message");

        final notification = message['data'];
        if(notification['title']!=null){
            if(notification['title']=="Testo"){
              goToAppointmentsScreen(currentUser,context);

            }
          }
      },
      onResume: (Map<String, dynamic> message) async {
        print("onResume: $message");

        final notification = message['data'];
        if(notification['title']!=null){
            if(notification['title']=="Testo"){
              goToAppointmentsScreen(currentUser,context);

            }
          }
      },
    );
    _isConfigured = true;
    }

  }
    
    
  }

  void goToAppointmentsScreen(User currentUser1, BuildContext context1) async {
    final bool backFromAppointmentsScreen=await Navigator.push(
            context1,
            MaterialPageRoute(builder: (context) => Appointment( 
              currentUser1),
            ),
            );
  }

希望对您有帮助

Answer 3

我知道，这有点丑陋，但我只有这样知道：

添加flutter_local_notifications
import 'package:flutter_local_notifications/flutter_local_notifications.dart';

只需创建final fln = FlutterLocalNotificationsPlugin();
，并在需要时使用fln.cancelAll()。

Answer 4

为了防止 onLaunch 和 onResume 方法一次又一次地运行，我所做的是用最后一个通知检查当前通知（我使用 shared_preferences）

这是片段：

_firebaseMessaging.configure(
    onMessage: (Map<String, dynamic> message) async {
      print('on message $message');
      onMessageReceived(context, message);
    },
    onResume: (Map<String, dynamic> message) async {
      print('on resume $message');
      onLaunch(context, message);
    },
    onLaunch: (Map<String, dynamic> message) async {
      print('on launch $message');
      onLaunch(context, message);
    },
  );

.
.
.

void onLaunch(BuildContext context, Map<String, dynamic> remoteMessage) async {
  var pref = SharedPreferences.getInstance();

  var data = remoteMessage['data'] ?? remoteMessage;
  String lastData = '';

  await pref.then((prefs) {
    lastData = prefs.get('remote_message');
  });

  if ((data['type'] != null || data['id'] != null) &&
      data.toString() != lastData) {

    toDetailPageFromPush(
      context,
      data['type'],
      data['id'],
    );
    pref.then((prefs) {
      prefs.setString('remote_message', data.toString());
    });
  } else {
    print('on launch error $remoteMessage');
  }
}

Answer 5

这是另一种解决方案，使用通知中的唯一值 message_id，因此我们可以使用共享首选项保存通知的最后一个 id 并与当前通知进行比较：

processNotification(message, BuildContext context) async {
 try {

  SharedPreferences sharedPreferences = await SharedPreferences.getInstance();
 
  String lastMessageId = sharedPreferences.getString('last_message_id');
  String currentMessageId = message['data']['google.message_id'];

  //COMPARE NOTIFICATIONS ID
  if(currentMessageId != lastMessageId) {
    
     //SET LAST NOTIFICATION ID
     sharedPreferences.setString('last_message_id', currentMessageId);
 
     //SHOW A DIALOG OR NAVIGATE TO SOME VIEW, IN THIS CASE TO A VIEW
     String screen = message['data']['screen'];
     Navigator.of(context).pushNamed(screen);
  }
} catch (e) {
  print('ERROR PROCESSING NOTIFICATION');
  print(e);
 }
}

现在我们可以在配置中调用这个函数了：

 _firebaseMessaging.configure(
  onMessage: (Map<String, dynamic> message) async {
    print('on message $message');
    processNotification(context,message);
  },
  onResume: (Map<String, dynamic> message) async {
    print('on resume $message');
    processNotification(context,message);
  },
  onLaunch: (Map<String, dynamic> message) async {
    processNotification(context,message);
  },
);

firebase_messaging如何清除通知？

5 个答案: