如何将下面的Spring Integration XML配置转换为Java配置bean。
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:int="http://www.springframework.org/schema/integration"
xmlns:int-http="http://www.springframework.org/schema/integration/http"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/integration
http://www.springframework.org/schema/integration/spring-integration.xsd
http://www.springframework.org/schema/integration/http
http://www.springframework.org/schema/integration/http/spring-integration-http.xsd">
<int:channel id='reply.channel'>
<int:queue capacity='10' />
</int:channel>
<int:channel id='get.request.channel'/>
<int-http:outbound-gateway id="outbound.gateway"
request-channel="get.request.channel" url="{fhirurl}"
http-method-expression="payload.getHttpMethod()" expected-response-type-expression="payload.getResponseType()"
charset="UTF-8" reply-timeout="5000" reply-channel="reply.channel">
<int-http:uri-variable name="fhirurl" expression="payload.getUrl()"/>
</int-http:outbound-gateway>
</beans>
我得到了以下代码,但无法使用 您能帮我在soapHeaderMapper和requestFactory中写些什么吗?
@Bean
public IntegrationFlow httpOut() {
return IntegrationFlows.from("reply.channel")
.handle(Http.outboundGateway("http://localhost:8080/")
.charset("UTF-8")
.httpMethod(HttpMethod.GET)
.headerMapper(soapHeaderMapper())
.requestFactory(requestFactory()), e -> e.id("test"))
.get();
}
高级谢谢