Question

我有一个JSON文件，我想将该JSON数据作为键，值对进行处理。

这是我的JSON文件

```"users" : {
        "abc": {
            "ip": "-------------",
            "username": "users@gmail.com",
            "password": "---------",
            "displayname": "-------",
            "Mode": "-----",
            "phonenumber": "1********1",
            "pstndisplay": "+1 *******5"
        },
        "efg": {
            "ip": "-------------",
            "username": "user1@gmail.com",
            "password": "---------",
            "displayname": "-------",
            "Mode": "-----",
            "phonenumber": "1********1",
            "pstndisplay": "+1 *******5"
        },
        "xyz": {
            "ip": "-------------",
            "username": "user2@gmail.com",
            "password": "---------",
            "displayname": "-------",
            "Mode": "-----",
            "phonenumber": "1********1",
            "pstndisplay": "+1 *******5"```

在这里我尝试获取json数据

 ``` ${the file as string}=    Get File    ${users_json_path}
  ${parsed}=    Evaluate  json.loads("""${the file as string}""")    json
  ${properties}=  Set Variable  ${parsed["users"]}
  Log  ${properties}
  :FOR    ${key}    IN    @{properties}
  \  ${sub dict}=    Get From Dictionary    ${properties}    ${key}
  \  Log  ${sub dict}
  \  Signin  ${sub dict}[ip]   ${sub dict}[username]   ${sub dict}[password]  ${sub dict}[Mode]
  \  Log  ${key} is successfully signed in.

预期的行为-我正在解析的键应该从JSON文件开始按顺序排列。例如，abc首先登录，然后efg和xyz。

${key} = abc
${key} = efg
${key} = xyz

以下是问题： 1）我们如何按顺序从JSON吸引用户？现在随机 2）什么是实现这一目标的最佳逻辑？

Answer 1

#!/usr/bin/env python3
import json

def main():
    json_str = """
    {
        "users" : {
            "abc": {
                "ip": "-------------",
                "username": "users@gmail.com",
                "password": "---------",
                "displayname": "-------",
                "Mode": "-----",
                "phonenumber": "1********1",
                "pstndisplay": "+1 *******5"
            },
            "efg": {
                "ip": "-------------",
                "username": "user1@gmail.com",
                "password": "---------",
                "displayname": "-------",
                "Mode": "-----",
                "phonenumber": "1********1",
                "pstndisplay": "+1 *******5"
            }
        }
    }
    """
    json_object = json.loads(json_str)
    for line in json_str.split('\n'):
        if '"' in line and ':' in line and '{' in line and '"users"' not in line:
            key = line.split('"')[1]
            print(key, json_object['users'][key])

Answer 2

我看到您用python 2.7标记了这个问题-Bryan Oakely的注释完全正确，元素按随机顺序排列。
但是，如果您升级到python 3，则从v3.6开始，字典将保证保留插入顺序。因此，使用json库进行解析时，结果将与源字符串/文件中的结果相同。

或者，在v2中，您可以使用OrderedDict完成相同的操作-另外，将JSONDecoder的参数object_pairs_hook指定为-您基本上会指定结果为{{ 1}}：

OrderedDict

我们如何以原始顺序从json获取密钥？

2 个答案: