Question

我已经尝试了堆栈溢出中的所有解决方案，但找不到确切的解决方案或问题答案。当我尝试使用getTime（）转换日期时，有时会显示负值，有时是数字与手动计算的天数相比，答案中显示的天数似乎不正确。我添加了用于计算的代码。请看看。

引荐：Difference between two dates in years, months, days in JavaScript

var date2 = new Date("2018-01-01");
var date1 = new Date("2017-01-01");


var diff = Math.floor(date2.getTime() - date1.getTime());
//1000*60*60*24
var secs = Math.floor(diff / 1000);
var mins = Math.floor(secs / 60);
var hours = Math.floor(mins / 60);
var days = Math.floor(hours / 24);
var months = Math.floor(days / 31);
var years = Math.floor(months / 12);
months = Math.floor(months % 12);
days = Math.floor(days % 31);
hours = Math.floor(hours % 24);
mins = Math.floor(mins % 60);
secs = Math.floor(secs % 60);
var message = "";
if (days <= 0) {
  message += secs + " sec ";
  message += mins + " min ";
  message += hours + " hours ";
} else {
  message += days + " days ";
  if (months > 0 || years > 0) {
    message += months + " months ";
  }
  if (years > 0) {
    message += years + " years ago";
  }
}
console.log(message);

//Expected result is : 1 year 0 months 0 days.


//Actual result is : 11 months 24 days.

Answer 1

一个月中没有31天。在非-年中，有30.417天。

Answer 2

尝试这样，但与您的预期结果不同。12 months等于1 year。

我的代码的结果是1 Year 0 Months 0 Days。

var date2 = new Date("2021-01-01")
var date1 = new Date("2020-01-01");

function getdiff(date2, date1) {

  var yeardate2 = date2.getYear();
  var monthdate2 = date2.getMonth();
  var datedate2 = date2.getDate();
  var yeardate1 = date1.getYear();
  var monthdate1 = date1.getMonth();
  var datedate1 = date1.getDate();
  var diff = {};
  var res = "";
  var yearString = "";
  var monthString = "";
  var dayString = "";


  yearTot = yeardate2 - yeardate1;

  if (monthdate2 >= monthdate1)
    var monthTot = monthdate2 - monthdate1;
  else {
    yearTot--;
    var monthTot = 12 + monthdate2 -monthdate1;
  }

  if (datedate2 >= datedate1)
    var dateTot = datedate2 - datedate1;
  else {
    monthTot--;
    var dateTot = 31 + datedate2 - datedate1;

    if (monthTot < 0) {
      monthTot = 11;
      yearTot--;
    }
  }

  diff = {
    years: yearTot,
    months: monthTot,
    days: dateTot
  };

  if ( diff.years > 1 ) yearString = " years ";
  else yearString = " year ";

  if ( diff.months> 1 ) monthString = " months ";
  else monthString = " month ";

  if ( diff.days > 1 ) dayString = " days ";
  else dayString = " day ";
   
  
  res = diff.years + yearString  + diff.months + monthString + diff.days + dayString;

  return res;
}


console.log(getdiff(date2, date1))

如何找到两个日期之间的差异，并使用Java脚本使用年，月和日的天数显示它？

2 个答案: