自定义Django身份验证时出现密码错误

时间:2019-05-07 22:09:03

标签: django django-authentication

我正在尝试使用已创建的Mysql表(协作者)来自定义Django默认情况下的身份验证。 当我想要注册用户(使用command python manage.py createsuperuser)时,出现以下错误:

django.db.utils.OperationalError: (1054, "Unknown column 'collaborators.password' in 'field list'").

该错误提到密码列不存在,并且实际上我在表中没有密码列,有没有办法表明密码是从名为contrasena_general的列中获得的? 我附上我的代码。

models.py

class MyUserManager(BaseUserManager):
    use_in_migrations = True

    def create_superuser(self, no_colaborador, nombres_colaborador, apellido_paterno_colaborador, apellido_materno_colaborador,
                        id_plantel, id_area_colaborador, no_empleado_sup, contrasena_general, empleado_interno):

        user = self.model(no_colaborador = no_colaborador, nombres_colaborador = nombres_colaborador, 
            apellido_paterno_colaborador = apellido_paterno_colaborador, apellido_materno_colaborador = apellido_materno_colaborador,
            id_plantel = id_plantel, id_area_colaborador = id_area_colaborador, no_empleado_sup = no_empleado_sup, 
            contrasena_general = contrasena_general, empleado_interno = empleado_interno,)
        user.set_password(contrasena_general)
        user.save(using=self._db)
        return user

class Colaboradores(AbstractBaseUser):
    no_colaborador = models.IntegerField(primary_key=True)
    nombres_colaborador = models.CharField(max_length=150)
    apellido_paterno_colaborador = models.CharField(max_length=150)
    apellido_materno_colaborador = models.CharField(max_length=150)
    id_plantel = models.IntegerField()
    id_area_colaborador = models.IntegerField()
    id_centro_costos = models.IntegerField()
    no_empleado_sup = models.IntegerField()
    contrasena_general = models.CharField(max_length=100)
    empleado_interno = models.CharField(max_length=10)

    objects = MyUserManager()

    USERNAME_FIELD = "no_colaborador"

    class Meta:
        managed = False
        db_table = 'collaborators'
        app_label = "journal"

    def __str__ (self): 
        return self.email 

    def def_full_name (self): 
        return self.nombres_colaborador

    def has_perm(self, perm, obj=None):
        return self.no_colaborador

    def has_module_perms(self, app_label):
        return self.no_colaborador
# backends.py

class MyAuthBackend(object):
    def authenticate(self, no_colaborador, contrasena_general):    
        try:
            user = Colaboradores.objects.get(no_colaborador=no_colaborador)
            if user.check_password(contrasena_general):
                return user
            else:
                return None
        except Colaboradores.DoesNotExist:
            logging.getLogger("error_logger").error("user with login %s does not exists " % login)
            return None
        except Exception as e:
            logging.getLogger("error_logger").error(repr(e))
            return None

    def get_user(self, no_colaborador):
        try:
            user = Colaboradores.objects.get(no_colaborador=no_colaborador)
            if user.is_active:
                return user
            return None
        except Colaboradores.DoesNotExist:
            logging.getLogger("error_logger").error("user with %(no_colaborador)d not found")
            return None
# setting.py
...
AUTH_USER_MODEL = 'journal.Colaboradores'
AUTHENTICATION_BACKENDS = ('clientes.backends.MyAuthBackend', 'django.contrib.auth.backends.ModelBackend',)

您如何指示密码是从表中未称为密码的列中获取的?

1 个答案:

答案 0 :(得分:0)

我认为创建自己的createsuperuser命令将解决此问题。

参考:Is it possible to make my own createsuperuser command in django?

您可以基于在Github上可以找到的Django's createsuperuser的原始源代码。

从那里可以看到,第20行有一个常量,表示:

PASSWORD_FIELD = 'password'

所以我想,由于您已在模型中将其更改为contrasena_general,因此您需要创建自己的自定义命令。