oneL.c：79：1：错误：预期的标识符或'（'在'}'令牌之前

Question

我知道这是一个语法错误，但是我找不到它，并且已经检查了大约30分钟。它之前编译过，更改了mult函数中的某些内容，然后出现此错误。我知道这有时是愚蠢的解决方案，这是一个普遍的问题，如果我错过了一些东西，请道歉。

#include <omp.h>
#include <stdio.h>
#include <stdlib.h>
#include <sys/time.h>
#include <time.h>
#include <unistd.h>

//MAX SIZE OF MATRIX
#define MAX_SIZE 3000

void mult(int size, int *threads);
double get_seconds();

//GLOBAL MATRIXIES (Matricies?)
volatile float a[MAX_SIZE][MAX_SIZE];
volatile float b[MAX_SIZE][MAX_SIZE];
volatile float c[MAX_SIZE][MAX_SIZE];

int main(int argc, char **argv) {
    int size, threads, i, j, check = 0;
    double start, end, timeF;

    while (check == 0) {
        printf("Enter <size of Matrix>, <Nuber of Threads>:");
        scanf("%d, %d", size, threads);

        if ((size > MAX_SIZE) || (size <= 0)) 
            printf("Incorrect size for matix, please input a number between 1 and %d\n", MAX_SIZE);
        else 
            check = 1; 
    }

    srand(time(NULL));

    //MAKE MATRIX
    for (i = 0; i < size; i++) {
        for (j = 0; j < size; j++) {
            a[i][j] = (float)rand() / 10000;
            b[i][j] = (float)rand() / 10000;
        }
    }

    start = get_seconds();

    /* Timed matrix-multiplication */
    mult(size, &threads);

    /* Get end_time & calculate exec_time*/
    end = get_seconds();
    timeF = end - start;

    timeF = timeF * 1000;

    printf("Threads %d took %f time.\n", threads, timeF);

    return 0;
}

void mult(int size, int * threads) {
    int i, j, k;

    for (i = 0; i < size; i++) {
        for (j = 0; j < size; j++) {
            c[i][j] = 0;

            #pragma omp parallel shared(a, b, c, size) { 

                *threads = omp_get_num_threads();

                #pragma omp for schedule(static)
                for (k = 0; k < size; k++) {
                    c[i][j] += a[i][k] * b[k][j];
                }
            }
        }
    }
}

double get_seconds() {
    struct timeval tvs;
//  struct timezone tzs;

    gettimeofday(&tvs, NULL);

    return((double)tvs.tv_sec + (double)(tvs.tv_usec * 1.e-6));
}

现在只需要编译即可