Question

class PersonDTO {
  String name;
  String street;
  String city;
}
class Person {
  String name;
  Address address;
}
class Address {
  String street;
  String city;
}

@Mapper(componentModel = "spring")
interface Mapper {
  Person fromPersonDTO(PersonDTO dto);
}

我尝试使用2 String到Address，但它抛出

模糊属性异常

。

我应该在映射器中添加些什么，以将street中的city和PersonDTO映射到Address？

更新：

@Mapper(componentModel = "spring")
interface Mapper {
  @Mapping(source = "street", target = "address.street")
  @Mapping(source = "city", target = "address.city")
  Person fromPersonDTO(PersonDTO dto);
}

以上映射器可以处理直接映射。但是，如果我在创建Address对象

时想添加一些业务逻辑怎么办？

例如：

address.street = street.replaceAll(" ", "_"); 
address.city = cityDao.findByName(city).getId();

有没有办法达到这种要求？

Answer 1

@Mapper(componentModel = "spring")
interface Mapper {

    @Mappings({
            @Mapping(source = "street", target = "address.street"),
            @Mapping(source = "city", target = "address.city")
    })
    Person fromPersonDTO(PersonDTO dto);
}

属性name应该自动映射，只要它具有相同的名称和嵌套级别

更新：

@Mapper(componentModel = "spring")
public abstract class Mapper {

    @Autowired
    private CityDAO cityDao;

    @Mappings({
            @Mapping(source = "street", target = "address.street"),
            @Mapping(source = "city", target = "address.city")
    })
    Person fromPersonDTO(PersonDTO dto);

    @AfterMapping
    void after(@MappingTarget Person person) {
        Address address = person.getAddress();
        if (address != null) {
            // additional null-checks might be required
            address.setStreet(address.getStreet().replaceAll(" ", "_")); 
            address.setCity(cityDao.findByName(address.getCity()).getId();
        }
    }
}

请注意，要使用自动装配的bean，映射器必须是类，而不是接口

Mapstruct如何从源对象的2个或更多字段构造目标对象？

1 个答案: