Question

我有一个类似的数据数组：

var items  = [
  { id: 84, "completedDate":"2019-01-26T17:45:07.895Z" },
  { id: 92, "completedDate":"2019-02-26T17:45:07.895Z" }, 
  { id: 123, "completedDate":"2019-03-26T17:45:07.895Z" }, 
  { id: 2353, "completedDate":"2019-04-26T17:45:07.895Z" }
];

我想返回一个只有少于30天的对象的数组。

我尝试过滤

var filtered = items.filter(function(item) { 
  return moment(item.completedDate) > moment.subtract(30, 'days');  
});

这是我需要做的吗，还是有更好的方法呢？

Answer 1

您不需要moment来比较日期：

const compareDate = new Date();
compareDate.setDate(compareDate.getDate() - 30);

const filtered = items.filter(item => new Date(item.completedDate) > compareDate);

Answer 2

这是一种类似的方法，不需要moment。在这里，我们只获取当天的日期，将时间重置为当天的开始（您的用例可能需要也可能不需要），然后我们只使用普通的JS日期对象进行比较

var items  = [
  { id: 84, "completedDate":"2019-01-26T17:45:07.895Z" },
  { id: 92, "completedDate":"2019-02-26T17:45:07.895Z" }, 
  { id: 123, "completedDate":"2019-03-26T17:45:07.895Z" }, 
  { id: 2353, "completedDate":"2019-04-26T17:45:07.895Z" }
];

var thirtyDaysAgo = new Date();
thirtyDaysAgo.setHours(0, 0, 0, 0);
thirtyDaysAgo.setDate(thirtyDaysAgo.getDate() - 30);

var filtered = items.filter(function(item) { 
  var d = new Date(item.completedDate).getTime();
  return d > thirtyDaysAgo;  
});

console.log(filtered);

或者，一个更小的过滤器功能（如果不需要IE 11支持）将是：

var filtered = items.filter((item) => new Date(item.completedDate).getTime() > thirtyDaysAgo);

Answer 3

尝试

items.filter( x=> x.completedDate > today.toISOString() );

var items  = [
  { id: 84, "completedDate":"2019-01-26T17:45:07.895Z" },
  { id: 92, "completedDate":"2019-02-26T17:45:07.895Z" }, 
  { id: 123, "completedDate":"2019-03-26T17:45:07.895Z" }, 
  { id: 2353, "completedDate":"2019-04-26T17:45:07.895Z" }
];

var today = new Date("2019-04-20T17:45:07.895Z") // or: new Date() 
today = new Date(+today - 30 *86400000)

let r= items.filter( x=> x.completedDate > today.toISOString() );

console.log(r);

根据日期消除数组条目

3 个答案: