Question

我已重写save方法以从其他模型的字段继承。但是，我只想在创建对象时不传递该字段的值的情况下继承。如果在创建对象时传递了值，则我不希望它继承。

我有两个模型：

Product具有字段type（外键）和should_remove

Type具有字段name和should_remove

当我创建新产品条目而未传递should_remove时，它将自动从正确的Type继承。

type = Type.objects.create(name="open", should_remove=False)
product = Product.objects.create(type=type)
product.should_remove # False

但是，如果我传递了should_remove字段，它仍然继承自Type

type = Type.objects.create(name="open", should_remove=False)
product = Product.objects.create(type=type, should_remove=True)
product.should_remove # False

我的想法是在should_remove方法内访问传递的save()的值，并仅在传递时设置它。如何在save方法中访问传递的值？

def save(self, *args, **kwargs):
    # How do I access the passed should_remove here??
    if not self.id:
        self.should_remove = self.type.should_remove
    super(Product, self).save(*args, **kwargs)

Answer 1

尝试以下

def save(self, *args, **kwargs):
    # How do I access the passed should_remove here??
    should_remove = kwargs.get("should_remove")
    # . . .

仅在提供方法时才覆盖它的方法

1 个答案: