Question

当我尝试这样做时，我在编译某些数组时遇到了一些问题并且编译器会收到错误。我也试过像Arrays.sort那样做，但没有运气。

import java.util.Scanner;
public class CH6PA
{
    private static double difficulty;
    private static int score;
    private  double[] average = new double[7];

    public static void main(String[]args)
    {
        Scanner keyboard = new Scanner (System.in);

        do
        {
            System.out.println("Enter the level of difficulty (1.2-3.8)");
        difficulty = keyboard.nextDouble();
        }
            while (difficulty<1.2 || difficulty>3.8);


        int[] judge = new int[7];


        for(int i = 0; i<judge.length; i++)
        {
        System.out.println("Enter the difficulty score for each judge (0-10)");

            System.out.println("Enter the score for judge" + (i+1));
            judge[i]=keyboard.nextInt();
    while(score > 0 && score <=10);
        }

sort(judge, judge.length);
System.out.println("Average = " + (judge[3] + judge[4] + judge[5]));

}
}

Answer 1

while（得分＆gt; 0＆amp;＆amp;得分＆lt; = 10）;似乎是错的。得分的价值是什么？

为什么两个嵌套循环，其中while（）循环不会执行任何操作;。

Answer 2

分数没有分配给它，因此你要比较空值。

Answer 3

我相信你的意思是：

do {
    System.out.println("Enter the score for judge" + (i+1));
    judge[i]=keyboard.nextInt();
} while(judge[i] > 0 && judge[i] <=10);        }

目前，judge[i]将从int读取stdin（如果已编译）

该行：

while(score > 0 && score <=10);

现在没有任何意义，因此您会收到编译错误。

Java中的排序问题

3 个答案: