Question

我试图将我的数据库输出（目前每个孩子和孙子从某些类别分配给我）的输出限制为仅该孩子。这样就不会显示孙子。

我试图将递归限制为仅发生一次，但是它不起作用。我认为答案在于数据库查询，但我对数据库并不熟悉。

public function getChildCategories(&$result, &$categories, $level = 1)
{
    $db = EB::db();

    $ordering = $this->params->get('order', 'popular');
    $sort = 'desc';
    $total = (int) $this->params->get('count', 0);
    $hideEmptyPost = $this->params->get('hideemptypost', false);
    $language = EB::getCurrentLanguage();

    foreach ($result as $row) {
        // Initialize default structure
        $category = EB::table('Category');
        $category->bind($row);
        $category->cnt = $row->cnt;

        $categories[$row->id] = $category;
        $categories[$row->id]->childs = array();

        // Find child categories
        $query = array();
        $query[] = 'SELECT a.*, COUNT(' . $db->qn('b.id') . ') AS ' . $db->qn('cnt') . ',' . $db->Quote($level) . ' AS ' . $db->qn('level');
        $query[] = 'FROM ' . $db->qn('#__easyblog_category') . ' AS a';
        $query[] = 'LEFT JOIN ' . $db->qn('#__easyblog_post_category') . ' AS pc';
        $query[] = 'ON ' . $db->qn('a.id') . '=' . $db->qn('pc.category_id');
        $query[] = 'LEFT JOIN ' . $db->qn('#__easyblog_post') . ' AS b';
        $query[] = 'ON ' . $db->qn('b.id') . '=' . $db->qn('pc.post_id');
        $query[] = 'AND ' . $db->qn('b.published') . '=' . $db->Quote(EASYBLOG_POST_PUBLISHED);
        $query[] = 'AND ' . $db->qn('b.state') . '=' . $db->Quote(EASYBLOG_POST_NORMAL);
        $query[] = 'WHERE ' . $db->qn('a.published') . '=' . $db->Quote(1);
        $query[] = 'AND ' . $db->qn('parent_id') . '=' . $db->Quote($row->id);

        if ($language) {
            $query[] = 'AND(';
            $query[] = $db->qn('a.language') . '=' . $db->Quote($language);
            $query[] = 'OR';
            $query[] = $db->qn('a.language') . '=' . $db->Quote('');
            $query[] = 'OR';
            $query[] = $db->qn('a.language') . '=' . $db->Quote('*');
            $query[] = ')';
        }

        if (!$hideEmptyPost) {
            $query[] = 'GROUP BY ' . $db->qn('a.id');
        } else {
            $query[] = 'GROUP BY ' . $db->qn('a.id') . ' HAVING (COUNT(' . $db->qn('b.id') . ') > 0)';
        }

        if ($ordering == 'ordering') {
            $query[] = ' ORDER BY `lft` desc';
        }

        if ($ordering == 'popular') {
            $query[] = ' ORDER BY `cnt` desc';
        }

        if ($ordering == 'alphabet') {
            $query[] = ' ORDER BY a.`title` asc';
        }

        if ($ordering == 'latest') {
            $query[] = ' ORDER BY a.`created` desc';
        }

        $query = implode(' ', $query);
        $db->setQuery($query);
        $children = $db->loadObjectList();
        $ccounter = 0;

        // Recursion happens here
        if ($children) {
            $this->getChildCategories($children, $categories[$row->id]->childs, ++$level);
        }
    }
}

有人可以向我解释如何修改数据库查询吗？现在的输出是：

Category
-Child Cat
--Grandchild Cat
-Child Cat

我想要：

Category
-Child Cat
-Child Cat

Answer 1

用户mickmackusa的评论解决了该问题。他的解决方案效果很好！

Rails.application.routes.draw do

  resources :allergies
  resources :prescriptions
  resources :issues

  get 'issues/:id/resolve' => 'issues#resolve', as: :resolve_issue

  get 'notes/:id/sign' => 'notes#sign', as: :sign_note
  get 'notes/:id/hide' => 'notes#hide', as: :hide_note

  get 'patients/:id/show' => 'patients#show', as: :show_patient

  resources :notes
  resources :observations
  resources :patients

end

如何将孙辈排除在递归查询过程之外？

1 个答案: