Question

我正在尝试与当前进程的子进程运行相同的进程。下面显示的代码在Windows下工作正常，但在Linux中失败并出现错误

找不到与命令“ dotnet-MyDll.dll”匹配的可执行文件

var processInfo = new ProcessStartInfo
        {
            FileName = "dotnet",
            Arguments = "MyDll.dll " + id.ToString()
        };

        Console.WriteLine("Starting child process...");
        var process = Process.Start(processInfo);
        return process;

我也尝试过 FileName =“ dotnet MyDll.dll” + id.ToString（），但最终会出现不同的错误未处理的异常：System.ComponentModel.Win32Exception：没有这样的文件或目录

我也尝试过

    var parentP = Process.GetCurrentProcess();
    string fullPath = parentP.MainModule.FileName;
    var command = fullPath+" "+Assembly.GetEntryAssembly().Location+" "+ id.ToString();
    Console.WriteLine("Command = "+command);
    var processInfo = new ProcessStartInfo
    {
        FileName = command
    };
    var process = Process.Start(processInfo);

仍然未处理的异常：System.ComponentModel.Win32Exception：没有这样的文件或目录

我也尝试过：

var parrentP = Process.GetCurrentProcess();
    string fullPath = parrentP.MainModule.FileName;
    var command = "\"" + fullPath + "\" " ;
    var args = Assembly.GetEntryAssembly().Location + " " + id;
    var processInfo = new ProcessStartInfo
    {
        FileName = command,
        Arguments = args
    };
        var process = Process.Start(processInfo);

Exception No such file or directory
Exception at System.Diagnostics.Process.StartCore(ProcessStartInfo startInfo)
at System.Diagnostics.Process.Start()
at System.Diagnostics.Process.Start(ProcessStartInfo startInfo)

在具有dotnet核心的Linux下再次运行当前正在运行的dll的正确方法是什么

ProcessInfo Linux / Windows不兼容

0 个答案: