Question

我目前正在处理一些代码，该代码可打印列表中最大的项目，然后删除该最大的项目。重复此操作，以降序打印项目。

列表的每个部分均包含志愿者姓名，他们已计算的行李总数以及其准确性。该算法检查精度最高的零件，然后打印所有上述三个变量。

不幸的是，我不知道如何找到列表最大部分（索引）的位置，不允许我删除它。

我已经尝试使用list.index命令以及仅键入del[maximum = max(VolunteerList, key = operator.itemgetter(2))]都无法使用。

Volunteer1TotalBags = 5
Volunteer2TotalBags = 23
Volunteer3TotalBags = 567
Volunteer4TotalBags = 12
Volunteer5TotalBags = 90
Volunteer6TotalBags = 11

Volunteer1Accuracy = 12
Volunteer2Accuracy = 65
Volunteer3Accuracy = 3
Volunteer4Accuracy = 5
Volunteer5Accuracy = 345
Volunteer6Accuracy = 43

def Option1():
    global Volunteer1Forename
    global Volunteer2Forename
    global Volunteer3Forename
    global Volunteer4Forename
    global Volunteer5Forename
    global Volunteer6Forename
    global Volunteer1Surname
    global Volunteer2Surname
    global Volunteer3Surname
    global Volunteer4Surname
    global Volunteer5Surname
    global Volunteer6Surname
    VolunteerData() # This calls back the variables above from a previous function
    Volunteer1FullName = Volunteer1Forename + Volunteer1Surname + "'s Total Bags and Accuracy"
    Volunteer2FullName = Volunteer2Forename + Volunteer2Surname + "'s Total Bags and Accuracy"
    Volunteer3FullName = Volunteer3Forename + Volunteer3Surname + "'s Total Bags and Accuracy"
    Volunteer4FullName = Volunteer4Forename + Volunteer4Surname + "'s Total Bags and Accuracy"
    Volunteer5FullName = Volunteer5Forename + Volunteer5Surname + "'s Total Bags and Accuracy"
    Volunteer6FullName = Volunteer6Forename + Volunteer6Surname + "'s Total Bags and Accuracy"
    VolunteerList = {(Volunteer1FullName, Volunteer1TotalBags, Volunteer1Accuracy), (Volunteer2FullName, Volunteer2TotalBags, Volunteer2Accuracy), (Volunteer3FullName, Volunteer3TotalBags, Volunteer3Accuracy), (Volunteer4FullName, Volunteer4TotalBags, Volunteer4Accuracy), (Volunteer5FullName, Volunteer5TotalBags, Volunteer5Accuracy), (Volunteer6FullName, Volunteer6TotalBags, Volunteer6Accuracy)}
    maximum = max(VolunteerList, key = operator.itemgetter(2))
    maximumindex = VolunteerList.index(max(VolunteerList, key = operator.itemgetter(2)))
    print(maximum)
    del[maximumindex]
Option1()

这是我得到的错误，这是因为程序无法为列表的最大部分生成索引：

maximumindex = VolunteerList.index(max(VolunteerList, key = operator.itemgetter(2)))
AttributeError: 'set' object has no attribute 'index'

请告诉我您是否不了解我的困境，我不知道我的措词是否足够清楚。

Answer 1

您要在此处创建set。

VolunteerList = {(Volunteer1FullName, Volunteer1TotalBags, Volunteer1Accuracy), (Volunteer2FullName, Volunteer2TotalBags, Volunteer2Accuracy), (Volunteer3FullName, Volunteer3TotalBags, Volunteer3Accuracy), (Volunteer4FullName, Volunteer4TotalBags, Volunteer4Accuracy), (Volunteer5FullName, Volunteer5TotalBags, Volunteer5Accuracy), (Volunteer6FullName, Volunteer6TotalBags, Volunteer6Accuracy)}

set不支持索引。您可能需要一个list

VolunteerList = [(Volunteer1FullName, Volunteer1TotalBags, Volunteer1Accuracy), (Volunteer2FullName, Volunteer2TotalBags, Volunteer2Accuracy), (Volunteer3FullName, Volunteer3TotalBags, Volunteer3Accuracy), (Volunteer4FullName, Volunteer4TotalBags, Volunteer4Accuracy), (Volunteer5FullName, Volunteer5TotalBags, Volunteer5Accuracy), (Volunteer6FullName, Volunteer6TotalBags, Volunteer6Accuracy)]

将{替换为[

如何删除列表中的最大变量

1 个答案: