我有一个如下数据框。我想用“ 3S”进行采样
因此,在某些情况下存在NaN。我期望的是数据帧应使用“ 3S”进行采样,并且如果在两者之间发现任何“ NaN”,则应从此处停止并从该索引开始采样。我尝试使用dataframe.apply
方法来实现,但看起来非常复杂。有什么短途可达成吗?
df.sample(n=3)
生成输入的代码:
index = pd.date_range('1/1/2000', periods=13, freq='T')
series = pd.DataFrame(range(13), index=index)
print series
series.iloc[4] = 'NaN'
series.iloc[10] = 'NaN'
我尝试进行采样,但是之后没有任何线索。
2015-01-01 00:00:00 0.0
2015-01-01 01:00:00 1.0
2015-01-01 02:00:00 2.0
2015-01-01 03:00:00 2.0
2015-01-01 04:00:00 NaN
2015-01-01 05:00:00 3.0
2015-01-01 06:00:00 4.0
2015-01-01 07:00:00 4.0
2015-01-01 08:00:00 4.0
2015-01-01 09:00:00 NaN
2015-01-01 10:00:00 3.0
2015-01-01 11:00:00 4.0
2015-01-01 12:00:00 4.0
新数据框应基于“ 3S”进行采样,如果存在,还应考虑“ NaN”,并从找到“ NaN”记录的位置开始采样。
预期输出:
2015-01-01 02:00:00 2.0 -- Sampling after 3S
2015-01-01 03:00:00 2.0 -- Print because NaN has found in Next
2015-01-01 04:00:00 NaN -- print NaN record
2015-01-01 07:00:00 4.0 -- Sampling after 3S
2015-01-01 08:00:00 4.0 -- Print because NaN has found in Next
2015-01-01 09:00:00 NaN -- print NaN record
2015-01-01 12:00:00 4.0 -- Sampling after 3S
答案 0 :(得分:1)
一种方法是用0填充NA:
combineLatest
然后对系列进行重采样: (如果datetime是您的索引)
df['Col_of_Interest'] = df['Col_of_Interest'].fillna(0)
答案 1 :(得分:1)
使用:
index = pd.date_range('1/1/2000', periods=13, freq='H')
df = pd.DataFrame({'col': range(13)}, index=index)
df.iloc[4, 0] = np.nan
df.iloc[9, 0] = np.nan
print (df)
col
2000-01-01 00:00:00 0.0
2000-01-01 01:00:00 1.0
2000-01-01 02:00:00 2.0
2000-01-01 03:00:00 3.0
2000-01-01 04:00:00 NaN
2000-01-01 05:00:00 5.0
2000-01-01 06:00:00 6.0
2000-01-01 07:00:00 7.0
2000-01-01 08:00:00 8.0
2000-01-01 09:00:00 NaN
2000-01-01 10:00:00 10.0
2000-01-01 11:00:00 11.0
2000-01-01 12:00:00 12.0
m = df['col'].isna()
s1 = m.ne(m.shift()).cumsum()
t = pd.Timedelta(2, unit='H')
mask = df.index >= df.groupby(s1)['col'].transform(lambda x: x.index[0]) + t
df1 = df[mask | m]
print (df1)
col
2000-01-01 02:00:00 2.0
2000-01-01 03:00:00 3.0
2000-01-01 04:00:00 NaN
2000-01-01 07:00:00 7.0
2000-01-01 08:00:00 8.0
2000-01-01 09:00:00 NaN
2000-01-01 12:00:00 12.0
说明:
Series.isna
比较缺失值Series.ne
(!=)进行比较,按连续值创建组print (s1)
2000-01-01 00:00:00 1
2000-01-01 01:00:00 1
2000-01-01 02:00:00 1
2000-01-01 03:00:00 1
2000-01-01 04:00:00 2
2000-01-01 05:00:00 3
2000-01-01 06:00:00 3
2000-01-01 07:00:00 3
2000-01-01 08:00:00 3
2000-01-01 09:00:00 4
2000-01-01 10:00:00 5
2000-01-01 11:00:00 5
2000-01-01 12:00:00 5
Freq: H, Name: col, dtype: int32
DatetimeIndex
进行比较|
,最后boolean indexing
个过滤器和bitwise OR
一个链式掩码