Question

要转发的第一个视图页面

<div class="row">
    <div class="col-lg-12 col-xs-12 col-sm-12 col-md-12">
        <select name="forwardto[]" class="form-control">
            <option value="">Select</option>
            <?php foreach($userlist as $row):?>
                <option value="<?php echo $row['cid']?>">
                    <?php echo $row['FirstName'].$row['MiddleName'].$row['LastName']?>
                </option>
                <?php endforeach;?>
        </select>
    </div>

内部控制器

function forward($param1='', $param2=''){
       $data1['message']='';
       $data['ForwarderId']=$this->session->userdata('cid');
       $data['ForwarderName']=$this->session->userdata('name');

       $data['Designation']=$this->session->userdata('position'); /* title ..I have created Designation in Stmessage table */

       $data1['RecieverId']=implode(', ', $_POST['forwardto']);
       $Rcid = implode(" ", $data1);
       $data['RecieverName']=$this->ag->name($Rcid);//this is not working
       //ag->is agency model

       $this->db->update('st_message', $data);
       if($this->db->affected_rows()>0){
          $dat['ReadStatus']='N';
          $this->db->where('Id', $param1);
          $this->db->update('st_message', $dat);

内部模型

public function name($Rcid)
   {
     $query=$this->db->query("SELECT CONCAT(e.FirstName, ' ',e.MiddleName, ' ', e. Lastname) as name, e.cid AS cid FROM bpas_user_profiles e
                             WHERE e.cid='".$Rcid."'");
    if ($query->num_rows() > 0)
    {
       return $query->row();              
    } else {
       return array();                
    }

}

实际上，选择了一个示例11112334的数据，并将其通过forwardto []传递给控制器。但是，当我将与forwardto []相关的$ Rcid作为参数传递给模型时，它无法获取。实际上，我想将数字示例111323232映射为表中的名称并对其进行更新

如何解决“未定义索引：forwardto []和implode（）：传递了无效参数”的问题

0 个答案: