Question

我最近一直在使用数组，在我的练习程序中，由于某种原因，它不会停止抛出语法错误，并且我的所有IDE告诉我都是意外的。据我所知，一切都很好。我只需要另一双眼睛。

我尝试从头开始重写并完全启动一个新文件。我什至卸载了python，然后重新安装。

import array as arr
employee_names = arr.array("u",[])
employee_hours = arr.array("u,",[])
employee_wage = arr.array("u",[])
input_employees = int(input("Type 1 if you want to start or 0 if you want to quit: ")

while input_employees == 1:
    input_names = input("Type in the names of the employees: ")
    employee_names.append(input_names)
    input_employees = int(input("If you want to enter more press 1 or if you are done press 0: ")
    if input_employees == 0:
        break
        print(employee_names)
    else:
    continue

但是运行它时，由于某种原因，您会在while语句中遇到语法错误。

Answer 1

我认为这应该可以正常工作

employee_names = []
employee_hours = []
employee_wage = []
input_employees = int(input("Type 1 if you want to start or 0 if you want to quit: "))
while input_employees:
    input_names = input("Type in the names of the employees: ")
    employee_names.append(input_names)
    input_employees = int(input("If you want to enter more press 1 or if you are done press 0: "))
    if not input_employees:
        break
    else:
        continue

请记住：

1）务必填写括号。

2）在开始编码之前学习语法。

注意：我没有修复您的算法，只是修复了可能的错误。

Answer 2

根据您给出的代码段

else:
continue

部分。 Python完全适用于缩进，因此在编写Python代码时请始终检查嵌套的缩进。这是没有错误的代码：-

import array as arr
employee_names = arr.array("u",[])
employee_hours = arr.array("u,",[])
employee_wage = arr.array("u",[])
input_employees = int(input("Type 1 if you want to start or 0 if you want to quit: ")

while input_employees == 1:
    input_names = input("Type in the names of the employees: ")
    employee_names.append(input_names)
    input_employees = int(input("If you want to enter more press 1 or if you are done press 0: ")
    if input_employees == 0:
        print(employee_names) // print before break
        break
    else:
       continue

此外，可以省略else部分，因为即使没有添加else部分，循环也会继续。

即使语法正确，Python也会抛出无效语法

2 个答案: