Question

我正在为一款猜谜游戏编写代码，用户可以为该数字选择一个范围，程序将选择一个随机数，并且用户可以猜测该数字，直到正确为止。

我尝试使用条件语句和while循环，但是无法运行它。

if (userGuess > targetNum):

    print "\nToo high\n"

elif (userGuess < targetNum):
        print "\nToo low\n"

else:
        print "\nThat's it! Nice job!\n"

此程序可以运行，但是我需要帮助使其循环运行，以便用户输入自己的猜测并获得反馈（如果它过高或过低，直到他们猜测正确的数字）。谢谢

Answer 1

您需要确保在成功案例中打破循环

targetNum = 5
while True:
    userGuess = int(input("Guess Number"))
    if (userGuess > targetNum):
        print("\nToo high\n")
        continue
    elif (userGuess < targetNum):
        print("\nToo low\n")
        continue
    #Break here
    else:
        print("\nThat's it! Nice job!\n")
        break

输出看起来像

Guess Number7

Too high

Guess Number9

Too high

Guess Number12

Too high

Guess Number5

That's it! Nice job!

Answer 2

添加将由条件触发的布尔值

wrong = True

while(wrong) : 
  if (userGuess > targetNum):
      print "\nToo high\n"
  elif (userGuess < targetNum):
      print "\nToo low\n"
  else:
      print "\nThat's it! Nice job!\n"
      wrong = False

Answer 3

您应该将IF语句放在while True:循环中。

userGuess = float(input("What's your guess? "))
targetNum = 10

while True:
    if userGuess > targetNum:
        print ("\n Too high\n")
        userGuess = float(input("What's your guess? "))
    elif userGuess < targetNum:
        print ("\n Too low\n")
        userGuess = float(input("What's your guess? "))
    else:
        print ("\n That's it! Nice job! \n")
        break

如何创建一个循环，允许用户输入内容，直到在Python中正确为止

3 个答案: