如何在网址路径的末尾添加“ /”？

Question

我的网址列中有一些网址。

www.quick.com/tea
www.quick.com/tea/green
www.quick.com/tea/green/strong
www.quick.com/tea/black/
www.quick.com/tea/black/light/

我需要在每个不以“ /”结尾的网址的末尾添加“ /”，并需要在所述列中获取所有网址。但这不会返回所有数据。有人可以帮助我获取正确的数据吗。

select concat(url,'/') as url
from table1
RIGHT(url, 1) != '/'

Answer 1

使用case逻辑：

select (case when url like '%/' then url else url || '/' end) as new_url

Answer 2

您可以同时使用decode和nvl2函数

with t(url) as
(
 select 'www.quick.com/tea' from dual union all
 select 'www.quick.com/tea/black/light/' from dual union all
 select null from dual   
)    
select nvl2(substr(url,-1),decode(substr(url,-1),'/',url,url||'/'),url) as new_url
  from t;

NEW_URL
------------------------------
www.quick.com/tea/
www.quick.com/tea/black/light/
/

Demo

nvl2适用于空URL的存在。否则，使用decode(substr(url,-1),'/',url,url||'/')就足以派生new_url列。