Question

我有两个日期作为datetime.date对象，在这两个日期（包括开始日期和结束日期除外）之间查找多个工作日的最Python化方法是什么？例如：

from datetime import date, timedelta

d1 = date(2019, 3, 1)
d2 = date(2019, 5, 6)
# The difference between d2 and d1 is 46 workdays

我想写一个循环：

workdays = 0
for i in range((d2 - d1).days):
    if (d1 + timedelta(days=i)).isoweekday() <= 5:
        workdays += 1

但是，我认为有一种更简单的方法可以解决此问题。

Answer 1

您可以尝试以下方法：

它不考虑假期，..：

import numpy as np
np.busday_count(d1.strftime("%Y-%m-%d"), d2.strftime("%Y-%m-%d"))

Answer 2

使用numpy函数busday_count：

from datetime import date
import numpy as np

d1 = date(2019, 3, 1)
d2 = date(2019, 5, 6)

days = np.busday_count( d1, d2 )
print (days)

或

from datetime import date,timedelta
d1 = date(2019, 3, 1)
d2 = date(2019, 5, 6)
daygenerator = (d1 + timedelta(x + 1) for x in range((d2 - d1).days)) # generate all days from d1 to d2
print (sum(1 for day in daygenerator if day.weekday() < 5))

如何在Python中找到两个日期之间的多个工作日？

2 个答案: