Question

我需要帮助来根据时间范围计算金额。另外，需要拿出整个月的计算结果。这是根据入住日期进行的轮班交易计算。

例如：班次01/05/2019开始于8:00:00，结束于02/05/2019 07:59:59 这是我的sql

Select CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120) Date, 
SUM(P.Amount - B.TourismTaxAmount) Amount 
From Bookings B 
Inner Join BookingPayments BP On B.ID = BP.BookingID 
Inner Join Payments P On P.ID = BP.PaymentID 
Where BookingStatus IN (2,3,4,6) and 
IsNull(CheckInDate, DateCheckIn) >= '2019-05-01 08:00:00' and
IsNull(CheckInDate, DateCheckIn) <= '2019-05-02 07:59:59'  
group by CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120) 
order by CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120)

以下是输出：

-------------------------
| Date         | Amount |
-------------------------
| 2019-05-01   | 123.00 |
| 2019-05-02   | 456.00 |
-------------------------

此SQL已经是正确的。。但是我如何使输出如下：

-------------------------
| Date         | Amount |
-------------------------
| 2019-05-01   | 579.00 |
-------------------------

并且从上面..我需要按日期生成月度班次摘要并输出如下：

-------------------------
| Date         | Amount |
-------------------------
| 2019-05-01   | 579.00 |
| 2019-05-02   | 891.00 |
| 2019-05-03   | 721.00 |
| ..........   | .....  |
| ..........   | .....  |
-------------------------

感谢您的帮助和解决方案。谢谢

Answer 1

按日期顺序使用窗口函数sum（）

Select CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120) Date, 
SUM(P.Amount - B.TourismTaxAmount) over(order by CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120)) Amount 
From Bookings B 
Inner Join BookingPayments BP On B.ID = BP.BookingID 
Inner Join Payments P On P.ID = BP.PaymentID 
Where BookingStatus IN (2,3,4,6) and 
IsNull(CheckInDate, DateCheckIn) >= '2019-05-01 08:00:00' and
IsNull(CheckInDate, DateCheckIn) <= '2019-05-02 07:59:59'  

order by CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120)

Answer 2

对于Sql-Server，我首先创建一个SQL，使用

以正确的格式显示Date-Column。

Select Year(myDate)*10000+Month(myDate)*100+Day(myDate) as MyNewDate ...

然后，如果您通过WITH在CTE中使用查询，则更容易对其进行分组。

Answer 3

只需减去8小时即可进行汇总。您可以通过所需的日期表达式轻松定义变量（井，列），从而得到：

Select convert(char(10), v.dte, 120) as Date, 
       sum(P.Amount - B.TourismTaxAmount) as Amount 
From Bookings B Inner Join
     BookingPayments BP
     On B.ID = BP.BookingID Inner Join
     Payments P
     On P.ID = BP.PaymentID cross apply
     (values (convert(date, dateadd(hour, -8, coalesce(CheckInDate, DateCheckIn))))
     ) v(dte)
Where BookingStatus in (2, 3, 4, 6) and 
      v.dte >= '2019-05-01' and
      v.dte < '2019-05-02'  
group by v.dte 
order by v.dte;

这也很容易扩展到多个日期或月份。

SQL查询以根据时间范围计算金额

3 个答案: