无法在名称为“ spring”的servlet中解析名称为“ streamrecords”的视图

时间:2019-05-06 05:10:58

标签: java spring spring-mvc java-8 tomcat7

我正在使用 Spring 4,Java 8,Tomcat 7 中的控制器示例中的简单流整数。

代码:

package com.entrib.emg.server.controller.rest;
import java.io.IOException;
import java.io.OutputStream;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.mvc.method.annotation.StreamingResponseBody;

@Controller
public class StreamRecordsController {

    @RequestMapping(value = "/streamrecords", method = RequestMethod.GET)
    public StreamingResponseBody handleRequest ()
            throws Exception {

        return new StreamingResponseBody() {
            @Override
            public void writeTo (OutputStream out) throws IOException {
                for (int i = 0; i < 1000; i++) {
                    out.write((Integer.toString(i) + " - ")
                                        .getBytes());
                    out.flush();
                    try {
                        Thread.sleep(5);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }
            }
        };
    }
}

错误:

Type Exception Report

Message Could not resolve view with name 'streamrecords' in servlet with name 'spring'

Description The server encountered an unexpected condition that prevented it from fulfilling the request.

Exception

javax.servlet.ServletException: Could not resolve view with name 'streamrecords' in servlet with name 'spring'
    org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1266)
    org.springframework.web.servlet.DispatcherServlet.processDispatchResult(DispatcherServlet.java:1041)
    org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:984)
    org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:901)
    org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:970)
    org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:861)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:624)
    org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:846)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:731)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
Note The full stack trace of the root cause is available in the server logs.

以下是快照:

enter image description here

问题:

我在这里想念什么

期望:

这只是一个简单的rest API代码,我期望当从浏览器或邮递员访问API时,会从此控制器流式传输整数。

-------------------------------------------- ----

已更新

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当我添加@ResponseBody时,我遇到了错误,

Type Status Report

Description The target resource does not have a current representation that would be acceptable to the user agent, according to the proactive negotiation header fields received in the request, and the server is unwilling to supply a default representation.

2 个答案:

答案 0 :(得分:0)

您在servlet方法上缺少@ResponseBody,或者可以使用@RestController标记您的类

答案 1 :(得分:0)

只需将类的注释更改为@RestController