Question

数据

Approval_ID
-----------
1
2
3
4
5
6
7
8
9
10

查询

DECLARE 
    @id varchar(8000)

SELECT  @id = COALESCE(@id + ', ', '') + '[' +  Approval_ID  + ']'
FROM (
   SELECT DISTINCT Approval_ID
   FROM Gate_III_CS_Approval
) Y

总是结果

1,10,2,3,4,5,6,7,8,9

我尝试添加“订购者”

ORDER BY len(Approval_ID), Approval_ID

但有错误

ORDER BY子句在派生的视图，内联函数中无效表，子查询和公用表表达式，除非TOP，OFFSET 或还指定了FOR XML。

我想要这样的结果

1,2,3,4,5,6,7,8,9,10

我该怎么办？

更新：

   ;with cte as (
        SELECT DISTINCT Approval_ID
        FROM Gate_III_CS_Approval
    )

    SELECT @id = STUFF(
                    (SELECT concat(',', '[' + Approval_ID + ']') 
                        FROM cte ORDER BY len(Approval_ID), Approval_id
                        FOR XML PATH('')
                    ), 1, 1, '')

Answer 1

使用CTE和STUFF for XML PATH

-- replace CTE with your table, this is only an example

declare @id varchar(8000) 

;with cte as (
 select 1 n 
 union all
 select n+1 n from
   cte 
   where n < 10
)
select @id = 
   STUFF((
            SELECT concat(',', n)
            FROM cte
            order by n
            FOR XML PATH('')
            ), 1, 1, '')



select @id

programmatically cast n from alphanumeric to int for sorting

Answer 2

为此，也许您可以尝试将varchar转换为int。我建立了一个示例here

DECLARE 
        @id varchar(8000)
    SELECT  @id = COALESCE(@id + ', ', '') + '[' +  CAST(ID AS VARCHAR(10))  + ']'
    FROM (
       SELECT DISTINCT CAST(id AS INT) ID
       FROM TABLA   
    ) Y

    SELECT  @ID

Answer 3

似乎您使用的是varchar字段，而不是Approval_ID的整数。

要根据varchar字段进行订购，可以尝试使用maSTAShuFu的答案中的方法。

在这里，我将使用问题中的查询进行更新。

SELECT STUFF(
    (SELECT CONCAT(',[', Approval_ID,']')
     FROM <your_table>
     ORDER BY cast(Approval_ID as int)
        FOR XML PATH('')), 1, 1, '')

将Select的结果插入到具有Order By的变量中

3 个答案: