Question

我正在使用Django建立新网站，并希望从中获取对象名称 sql。但是它保持输出错误对象.get匹配查询不存在我需要在哪里修改代码？

观看次数

import bs4
from selenium import webdriver
driver = webdriver.Chrome(executable_path=r"C:\Users\username\Downloads\chromedriver_win32\chromedriver.exe")
driver.get(url)

html = driver.page_source
soup = bs4.BeautifulSoup(html,'lxml')

for tag in soup.find_all("div", class_="jobDescriptionContent desc"):
    print (tag.text)

html

def predict1(request):
   name = ''
   loginstatus = False
   try:
        name = request.session['name']
        loginstatus = True
   except:
        return HttpResponseRedirect('/login/?back=未來型預測')


   category_id = FutureMember.objects.get(member_name=name).type
   cname = FutureFqType.objects.get(type_id=category_id).type_name
   return render_to_response('predicts.html', {'cname': cname,'loginstatus': loginstatus, 'name': name})

模型

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
</head>
<div><h2>根據投資人屬性測驗結果，您屬於<font color="#75CA20">{{ cname }} 您好!&nbsp;{{ name }}</font></h2>
    <form action="/predict/" method="post">
</div>
</body>
</html>

我希望{{cname}}的输出是数据，但实际无法输出出现错误FutureFqType匹配查询不存在。

新视图

class FutureFqType(models.Model):
    type_id = models.CharField(primary_key=True, max_length=2)
    type_name = models.CharField(max_length=20)
    type_describe = models.TextField(blank=True, null=True)
    type_score = models.CharField(max_length=20)

    class Meta:
        managed = False
        db_table = 'future_fq_type'

页面输出 enter image description here

Answer 1

 from django.shortcuts import HttpResponse, get_object_or_404, redirect, render


def predict1(request):
    loginstatus = False
    try:
        name = request.session["name"]
        loginstatus = True
    except KeyError:
        return redirect("/login/?back=未來型預測")
    try:
        member = FutureMember.objects.get(member_name=name)
    except FutureMember.DoesNotExist:
        msg = f"<h1>FutureMember not found with member_name=`{name}`</h1>"
        return HttpResponse(msg)
    try:
        fqtype = FutureFqType.objects.get(type_id=member.type)
    except FutureFqType.DoesNotExist:
        msg = f"<h1>FutureFqType not found with type_id=`{member.type}`</h1>"
        return HttpResponse(msg)
    else:
        cname = fqtype.type_name
    data = {"cname": cname, "loginstatus": loginstatus, "name": name}
    return render("predicts.html", data)

Django FutureFqType匹配查询不存在

1 个答案: