TypeError：obj [key] .includes不是函数：过滤器函数中

Question

我想找到具有某些属性的对象。但是我有一个错误：TypeError：obj [key] .includes不是一个函数。 如何解决？

var aa = [{id: 1,type: 1,status: 1,name: 'txt'},{id: 2,type: 1,status: 1,name: 'txt'},{id: 3,type: 0,status: 0,name: 'txt'}];

function filterIt(arr, searchKey) {
  return arr.filter(function(obj) {
    return Object.keys(obj).some(function(key) {
      return obj[key].includes(searchKey);
    })
  });
}

filterIt(aa, 'txt');

Answer 1

尝试改用Object.values：

var aa = [{id: 1,type: 1,status: 1,name: 'txt'},{id: 2,type: 1,status: 1,name: 'txt'},{id: 3,type: 0,status: 0,name: 'txt'}];

function filterIt(arr, searchKey) {
  return arr.filter(function(obj) {
    return Object.values(obj).includes(searchKey);
  });
}

console.log(filterIt(aa, 'txt'));

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您还可以使此代码更紧凑：

var aa = [{id: 1,type: 1,status: 1,name: 'txt'},{id: 2,type: 1,status: 1,name: 'txt'},{id: 3,type: 0,status: 0,name: 'txt'}];

const filterIt = (arr, searchKey) => arr.filter(obj => Object.values(obj).includes(searchKey));

console.log(filterIt(aa, 'txt'));

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Answer 2

采用对象的Object.values获取值的数组，然后您可以查看是否有任何值与searchKey匹配（尽管您正在搜索 values ，因此最好将其命名为valueToFind）：

var aa = [{
    id: 1,
    type: 1,
    status: 1,
    name: 'txt'
  },
  {
    id: 2,
    type: 1,
    status: 1,
    name: 'txt',
  },
  {
    id: 3,
    type: 0,
    status: 0,
    name: 'txt'
  },
  {
    id: 4,
    type: 0,
    status: 0,
    name: 'wrongname'
  },
];

function filterIt(arr, valueToFind) {
  return arr.filter(function(obj) {
    return Object.values(obj).includes(valueToFind);
  });
}

console.log(filterIt(aa, 'txt'));

由于您使用的是.some，请考虑使用ES6语法获取更简洁的代码：

var aa = [{
    id: 1,
    type: 1,
    status: 1,
    name: 'txt'
  },
  {
    id: 2,
    type: 1,
    status: 1,
    name: 'txt',
  },
  {
    id: 3,
    type: 0,
    status: 0,
    name: 'txt'
  },
  {
    id: 4,
    type: 0,
    status: 0,
    name: 'wrongname'
  },
];

const filterIt = (arr, valueToFind) => arr.filter(
  obj => Object.values(obj).includes(valueToFind)
);

console.log(filterIt(aa, 'txt'));