RegEx用于匹配句子中间的名字

Question

我试图捕获段落中的名称，并将其作为数组返回。具有名称的句子包含“ names are”。示例：

  

第一句话。一些第二句话。第三句和名字   是约翰，简，仁。这是关于其他内容的第四句话。

所需的输出：

[“约翰”，“简”，“简”]

尝试

paragraph.match(/names are ([A-Za-z ]+,{0,1} {0,1})+\./)

Answer 1

您可以使用names are ([^.]+)来匹配所有内容，直到下一个时期。然后使用split将名称获取到数组

const str = 'The first sentence. Some second sentence. Third sentence and the names are John, Jane, Jen. Here is the fourth sentence about other stuff.'

const regex = /names are ([^.]+)/,
      names = str.match(regex)[1],
      array = names.split(/,\s*/)

console.log(array)

Answer 2

您可以在匹配后使用split()

let str = `The first sentence. Some second sentence. Third sentence and the names are John, Jane, Jen. Here is the fourth sentence about other stuff.`

let res = str.match(/names are ([A-Za-z ]+,{0,1} {0,1})+\./g)[0].split(/\s+/g).slice(2)
console.log(res)