Question

我有两个4x4多维数组，行和列分别标记为A，B，C和D。当用户输入坐标时，所选的known_location_info的值将更改为bomb_location_info的值。因此，例如，如果输入了AA，则[1][1]上的known_location_info的值将变为[1][1]上的bomb_location_info的值。目前，无论输入什么坐标，我都只会更改第一个元素。我的循环中有什么错误？

char inputRow;
char inputColumn;
char letterA = 'A';

void display(int known_location_info[][DIM], int size) {

    printf("  A  B  C  D\n");

    for (int row = 0; row < DIM; row++) {

        printf("%c", letterA);
        letterA++;

        for (int column = 0; column < DIM; column++) {
            printf("%d ", known_location_info[row][column]);
        }
        printf("\n");
    }

    printf("Please select a row and column: ");
    scanf("%c, %c", &inputRow, &inputColumn);
}

void update_known_info(int row, int col, int bomb_location_info[][DIM], 
                       int known_location_info[][DIM]) {

    for (inputRow = letterA; inputRow < DIM; inputRow++) {
        for (inputColumn = letterA; inputColumn < DIM; inputColumn++) {
            row++;
            col++;
        }
    }

    known_location_info[row][col] = bomb_location_info[row][col];
}

Answer 1

使用从用户扫描的字符的访问矩阵不是一个好主意。因为每个字符都由ASCII码表示。因此，您将具有字母的ascii值的隐式偏移量（例如ASCII fo A =64。另一方面，矩阵就像数组。它们的索引从0开始。您可以在开始循环之前重新去除ascii偏移量。

Answer 2

#include <stdio.h>
#include <assert.h>

#define DIM 4

void display(int known_location_info[][DIM]) {

    printf("  A  B  C  D\n");

    for (int row = 0; row < DIM; ++row) {
        printf("%c ", 'A' + row);
        for (int column = 0; column < DIM; ++column)
            printf("%2d ", known_location_info[row][column]);
        putchar('\n');
    }

    printf("Please select a row and column: ");
    char inputRow; char inputColumn;
    if (scanf(" %c, %c", &inputRow, &inputColumn) != 2 ||
        inputRow < 'A' || 'A' + DIM < inputRow ||
        inputColumn < 'A' || 'A' + DIM < inputRow)
    {
        // handle input error
    }
}

void update_known_info(char row, char col, int bomb_location_info[][DIM],
                       int known_location_info[][DIM])
{
    row -= 'A';
    col -= 'A';

    assert(0 <= row && row < DIM && 0 <= col && col < DIM);

    known_location_info[row][col] = bomb_location_info[row][col];
}

如何使用循环访问矩阵元素

2 个答案: