Question

我的问题与Combining asyncio with a multi-worker ProcessPoolExecutor非常相似-但是略有变化（我相信是async for）使那里的出色答案对我来说毫无用处。

我正在尝试以下MWE：

import concurrent.futures
import asyncio
import time

async def mygen(u: int = 2):
    i = 0
    while i < u:
        yield i
        i += 1

def blocking(delay):
    time.sleep(delay+1)
    return('EXECUTOR: Completed blocking task number ' + str(delay+1))

async def non_blocking(loop):
    with concurrent.futures.ProcessPoolExecutor() as executor:
        async for i in mygen():
            print('MASTER: Sending to executor blocking task number ' + str(i+1))
            result = await loop.run_in_executor(executor, blocking, i)
            print(result)
            print('MASTER: Well done executor - you seem to have completed blocking task number ' + str(i+1))

loop = asyncio.get_event_loop()
loop.run_until_complete(non_blocking(loop))

按预期，此输出是非异步的：

MASTER: Sending to executor blocking task number 1
EXECUTOR: Completed blocking task number 1
MASTER: Well done executor - you seem to have completed blocking task number 1
MASTER: Sending to executor blocking task number 2 
EXECUTOR: Completed blocking task number 2 
MASTER: Well done executor - you seem to have completed blocking task number 2

我想调整代码，以使任务在两个并发进程中运行，并在输出可用时打印输出。所需的输出是：

MASTER: Sending to executor blocking task number 1
MASTER: Sending to executor blocking task number 2
EXECUTOR: Completed blocking task number 1
MASTER: Well done executor - you seem to have completed blocking task number 1
EXECUTOR: Completed blocking task number 2
MASTER: Well done executor - you seem to have completed blocking task number 2

从Combining asyncio with a multi-worker ProcessPoolExecutor我了解到，就目前情况而言，我await loop.run_in_executor()的语法正在阻塞。我不知道如何以一种允许async for移至下一个生成的值，同时等待执行者完成其工作的方式来替换它。请注意，我没有在他们的示例中使用asyncio.gather。

Answer 1

如果您最多要有两个进程来运行任务，那么最简单的实现方法是使用max_workers=2创建执行程序。然后，您可以尽快提交任务，即继续进行async for的下一个迭代，而不必等待上一个任务完成。您可以在最后收集所有任务的结果，以确保不会引起异常的注意（并可能获得实际结果）。

以下代码产生预期的输出：

from concurrent.futures import ProcessPoolExecutor
import asyncio
import time

async def mygen(u: int = 2):
    i = 0
    while i < u:
        yield i
        i += 1

def blocking(delay):
    time.sleep(delay+1)
    return('EXECUTOR: Completed blocking task number ' + str(delay+1))

async def run_blocking(executor, task_no, delay):
    print('MASTER: Sending to executor blocking task number '
          + str(task_no))
    result = await loop.run_in_executor(executor, blocking, delay)
    print(result)
    print('MASTER: Well done executor - you seem to have completed '
          'blocking task number ' + str(task_no))

async def non_blocking(loop):
    tasks = []
    with ProcessPoolExecutor(max_workers=2) as executor:
        async for i in mygen():
            # spawn the task and let it run in the background
            tasks.append(asyncio.create_task(
                run_blocking(executor, i + 1, i)))
        # if there was an exception, retrieve it now
        await asyncio.gather(*tasks)

loop = asyncio.get_event_loop()
loop.run_until_complete(non_blocking(loop))

将asyncio与多人ProcessPoolExecutor结合使用，并实现异步

1 个答案: