Question

我正在尝试从具有“ hierCd”和“ parentHierCd”的父子关系的那个表中的一个表中获取数据列表。我第一次得到所有父母名单。在那之后，当我建立数据时，我需要得到那些父母的所有孩子。就像我在预期结果中所示，这可能是多层次的。

表中的数据如下

  **hierCd**         **Name**         **parentHierCd**
   TEA-1               tea1              TEA
   TEA-2               tea2              TEA
   TEA-3               tea3              TEA
   TEAA-1              teaa-1            TEA-1
   TEAA-2              teaa-2            TEA-1
   TEAAA-1             teaaa-1           TEAA-1
   ITC-1               itc-1             ITC
   ITC-2               itc-2             ITC
   ITCA-1              itca-1            ITC-1
   ITCA-2              itca-2            ITC-1

我提到了所有代码。层是实体文件，是从数据库映射的。委员会正在使用其余api设置数据。

//Committee api model class
public class Committee {
    @JsonProperty("id")
    private UUID id = null;

    @JsonProperty("name")
    private String name = null;

    @JsonProperty("code")
    private String code = null;

    @JsonProperty("parentCd")
    private String parentCd = null;

    @JsonProperty("children")
    @Valid
    private List<Committee> children = null;

    with getters and setters
}

//Hier entity model class
public class Hier {
    private String hierCd;
    private String hierTyp;
    private String hierName;
    private String uuid;
    private String parentHierCd;

    with getters and setters

}

//This method is calling for get parent record.
public List<Committee> getCommittees(){

    private List<String> PARENT_CDS = Arrays.asList(new String[] { "TEA", "ITC" });

    List<Committee> committees = new ArrayList<>();
    List<Hier> committeeHierarchies = committeeRepository.findParentHiersByHierCdInOrderByHierNameAsc(PARENT_CDS);

    for(Hier hier:committeeHierarchies)
    {
        committees.add(committeeBuilder(hier));
    }

    return committees;

}

// Building committee with sub committee
private Committee committeeBuilder(Hier hier) {
    Committee committee = new Committee();
    committee.setId(UUID.fromString(hier.getUuid()));
    committee.setCode(hier.getHierCd());
    committee.setName(hier.getHierName());
    committee.setParentCd(hier.getParentHierCd());
    if(hiertype.equals("allCommittee")){
        committee.setChildren(getChildrenByParentCd(hier.getHierCd()));
    }
    return committee;
}

//Return sub committees by parent hier code
public List<Committee> getChildrenByParentCd(String parentCd) {
    List<Committee> committees = new ArrayList<>();
    List<Hier> children = committeeRepository.findChildrenByParentHierCd(parentCd);
    for (Hier hier : children) {
        Committee committee = new Committee();
        committee.setId(UUID.fromString(hier.getUuid()));
        committee.setCode(hier.getHierCd());
        committee.setName(hier.getHierName());
        committee.setParentCd(hier.getParentHierCd());
        committees.add(committee);
    }
    return committees;
}

上面的代码像下面这样返回，它只将数据返回到两个级别（父级和子级）中，但是我需要像下面提到的那样以递归的方式获取数据。

 > TEA 
   > TEA-1
   > TEA-2
   > TEA-3
 > ITC 
   > ITC-1
   > ITC-2

结果应如下所示

 > TEA 
   > TEA-1
     > TEAA-1
       > TEAAA-1
     > TEAA-2
   > TEA-2
   > TEA-3
 > ITC 
   > ITC-1
      > ITCA-1
      > ITCA-2
   > ITC-2

Answer 1

使用递归函数方法来解决此问题。就像需要查找子孩子是否可用于父对象。基于该叫委员会的Builder

如何在列表中设置子级？

1 个答案: