Question

此代码保存数据并根据需要显示数据。但是在显示课程时，它会显示为，]> 。 QuerySet []。i只希望显示课程名称。我该怎么做

models.py

class Teacher(models.Model):
    name = models.CharField(max_length=50)
    address = models.CharField(max_length=50)
    phone = models.CharField(max_length=15)
    email = models.EmailField()
    image = models.ImageField(upload_to='Teachers',blank=True)
    courses = models.ManyToManyField(Course)

views.py

def viewteacher(request):
        teachers = Teacher.objects.all().order_by('-joined_date')
        year1 = datetime.datetime.today().year

        return render(request,'students/view_teacher.html',{'teachers':teachers,'year_list':range(2016,year1+1)})

模板

  {% for teacher in teachers %}
                <tr> 
                    <td>{{teacher.name}}</div></td>
                        <td>{{teacher.courses.all}}</td>
                        <td>{{teacher.address}}</td>
                        <td>{{teacher.phone}}</td>
                        <td><a href="{% url 'students:profile_teacher' teacher.id %}">Profile</a></td>
                        <td><a href="{% url 'students:edit_teacher' teacher.id %}">Edit</a></td>
                        <td><a href="{% url 'students:confirm_delete_teacher' teacher.id %}">Delete</a></td>
                    </tr>
                   {% endfor %}
                </tbody>

Answer 1

QuerySet的呈现方式类似于<QuerySet [ ... ]>，因此您可以遍历查询集并正确呈现它，例如：

{% for teacher in teachers %}
<tr> 
    <td>{{teacher.name}}</div></td>
    <td>{% for course in teacher.courses %} {{course.name}} {% endfor %}</td>
    <td>{{teacher.address}}</td>
    <td>{{teacher.phone}}</td>
    <td><a href="{% url 'students:profile_teacher' teacher.id %}">Profile</a></td>
    <td><a href="{% url 'students:edit_teacher' teacher.id %}">Edit</a></td>
    <td><a href="{% url 'students:confirm_delete_teacher' teacher.id %}">Delete</a></td>
</tr>
{% endfor %}

但是，获取每位老师的课程列表并不是很有效。您可以使用.prefetch_related来加快此过程。然后它将执行有限数量的查询以获取所有课程，并将其正确链接到正确的教师：

def viewteacher(request):
    teachers = Teacher.objects.prefetch_related('courses').order_by('-joined_date')
    year1 = datetime.datetime.today().year

    return render(
        request,
        'students/view_teacher.html',
        {'teachers':teachers,'year_list':range(2016,year1+1)}
    )

如何在Django中正确显示多对多字段

1 个答案: