Question

我有以下选择语句，该语句在我的模式中的SQLPLUS中可以使用

select count(1) from gv$lock where id1 ='202';

但是我的函数中相同模式FN_GET_LOCK中的相同select语句在PLSQL中引发错误“表或视图不存在”

select count(1) into l_lockcnt from gv$lock where id1 = l_lock_hold;

任何想法如何使SQL语句在PLSQL中工作

此问题并非重复，因为我没有收到“权限不足错误”

Answer 1

您似乎通过角色获得了SELECT的{{1}}特权。如果是这样，那么-在命名的PL / SQL过程中将无法使用。您必须直接授予该特权给用户。

[编辑：关于角色]

一般来讲-不仅是关于角色的字典，它还是一个可供进一步研究的好资源。这是您可以用来查找该信息的示例查询：

gv$lock

让我们创建一个角色并为其授予一些特权：

SQL> select * from dictionary where lower(table_name) like '%role%';

TABLE_NAME                     COMMENTS
------------------------------ --------------------------------------------------
DBA_CONNECT_ROLE_GRANTEES      Information regarding which users are granted CONN
                               ECT

DBA_ROLES                      All Roles which exist in the database
DBA_ROLE_PRIVS                 Roles granted to users and roles
DBA_SCHEDULER_JOB_ROLES        All scheduler jobs in the database by database rol
                               e

USER_ROLE_PRIVS                Roles granted to current user
ROLE_ROLE_PRIVS                Roles which are granted to roles
ROLE_SYS_PRIVS                 System privileges granted to roles
ROLE_TAB_PRIVS                 Table privileges granted to roles
SESSION_ROLES                  Roles which the user currently has enabled.

9 rows selected.

SQL>

好的，所以-SQL> create role rl_scott_sel; Role created. SQL> grant select on emp to rl_scott_sel; Grant succeeded. SQL> grant select on bonus to rl_scott_Sel; Grant succeeded. SQL>包含什么？阅读上面的注释，这似乎是一个很好的起点。

ROLE_TAB_PRIVS

SQL中的SELECT语句有效，但PLSQL中的SELECT INTO语句无效

1 个答案: