我正在尝试在Python中创建如下所示的三角形镶嵌:
我得到的只是谢尔彭斯基的三角形。我认为它会使用一些相同的代码。
import turtle as t
import math
import colorsys
t.hideturtle()
t.speed(0)
t.tracer(0,0)
h = 0
def draw_tri(x,y,size):
global h
t.up()
t.goto(x,y)
t.seth(0)
t.down()
color = colorsys.hsv_to_rgb(h,1,1)
h += 0.1
t.color(color)
t.left(120)
t.fd(size)
t.left(120)
t.fd(size)
t.end_fill()
def draw_s(x,y,size,n):
if n == 0:
draw_tri(x,y,size)
return
draw_s(x,y,size/2,n-1)
draw_s(x+size/2,y,size/2,n-1)
draw_s(x+size/4,y+size*math.sqrt(3)/4,size/2,n-1)
draw_s(-300,-250,600,6)
t.update()
答案 0 :(得分:0)
有各种各样的方法;下面的示例在指示turtle
将它们绘制在画布上之前生成所有线段。
import turtle as t
import math
WIDTH, HEIGHT = 800, 800
OFFSET = -WIDTH // 2, -HEIGHT // 2
class Point:
"""convenience for point arithmetic
"""
def __init__(self, x=0, y=0):
self.x, self.y = x, y
def __add__(self, other):
return Point(self.x + other.x, self.y + other.y)
def __iter__(self):
yield self.x
yield self.y
def get_line_segments(side_length=50):
"""calculates the coordinates of all vertices
organizes them by line segment
stores the segments in a container and returns it
"""
triangle_height = int(side_length * math.sqrt(3) / 2)
half_side = side_length // 2
p0 = Point(0, 0)
p1 = Point(0, side_length)
p2 = Point(triangle_height, half_side)
segments = []
for idx, x in enumerate(range(-triangle_height, WIDTH+1, triangle_height)):
for y in range(-side_length, HEIGHT+1, side_length):
y += half_side * (idx%2 + 1)
offset = Point(x, y)
pa, pb, pc = p0 + offset, p1 + offset,p2 + offset
segments += [[pa, pb], [pb, pc], [pc, pa]]
return segments
def draw_segment(segment):
p0, p1 = segment
p0, p1 = p0 + offset, p1 + offset
t.penup()
t.goto(p0)
t.pendown()
t.goto(p1)
def draw_tiling():
for segment in get_line_segments():
draw_segment(segment)
t.hideturtle()
t.speed(0)
t.tracer(0,0)
offset = Point(*OFFSET)
draw_tiling()
t.update()
t.exitonclick()
如果要查看平铺的跟踪方式,可以替换以下行:
# t.hideturtle()
t.speed(1)
# t.tracer(0, 0)
并用鼠标放大画布屏幕以查看拼贴的边界(我将其与窗口的标准尺寸重叠)
答案 1 :(得分:0)
正如@ReblochonMasque所指出的,有多种解决方法。这是我制定的尽可能少使用乌龟代码来解决问题的方法:
-
它可能可以使用优化,但是可以完成工作。看着很有趣...