Question

我想对2D数组进行排序以匹配另一个数组的排名

我已经尝试过sorted()和sort()函数，但是它不起作用。我不确定我的格式是否错误，或者执行此操作的最佳方法是什么。

array = (32,96)
ranked =  [57, 23, 68, 58, 25, 91, 70, 83, 77, 75, 89, 34, 49, 79, 66, 54, 67,
       44, 63, 52, 46, 20, 64, 10, 80, 33, 30, 29, 28, 26, 17, 27, 50, 51,
       92, 86, 69, 47,  0,  7,  3, 85, 18, 11, 13, 53,  8, 78, 82, 81, 14,
       74, 59, 32, 42, 39,  1, 31, 36, 19, 24,  5, 38,  9, 73, 71, 76, 87,
       41, 55, 94, 93, 84, 16, 90, 62, 48, 43, 72, 95, 65, 45, 61, 22, 21,
       15, 37, 88,  2, 40, 56,  6, 12, 60,  4, 35]
sortedarray = sorted(array,ranked)

对于上面的代码，我得到一个错误：

TypeError: 'list' object is not callable

排名为96的值与原始数组的第二维相对应。

Answer 1

要对array的第二维进行排序，您可以先制作一个形状为（32，96）的空sortedarray，然后按ranked指定的顺序填写新数组。这是使用array的随机值的代码：

array = np.random.random((32,96))
ranked =  [57, 23, 68, 58, 25, 91, 70, 83, 77, 75, 89, 34, 49, 79, 66, 54, 67,
       44, 63, 52, 46, 20, 64, 10, 80, 33, 30, 29, 28, 26, 17, 27, 50, 51,
       92, 86, 69, 47,  0,  7,  3, 85, 18, 11, 13, 53,  8, 78, 82, 81, 14,
       74, 59, 32, 42, 39,  1, 31, 36, 19, 24,  5, 38,  9, 73, 71, 76, 87,
       41, 55, 94, 93, 84, 16, 90, 62, 48, 43, 72, 95, 65, 45, 61, 22, 21,
       15, 37, 88,  2, 40, 56,  6, 12, 60,  4, 35]

sortedarray = np.zeros(np.shape(array))
sortedarray[:, ranked] = array

按等级对2D排序

1 个答案: