Question

我想为我的播放列表模型创建详细信息视图。我遵循了docs的步骤，并且不断收到此错误：

AttributeError at /root
Generic detail view PlaylistDetail must be called with either an object pk or a slug in the URLconf.

这是我的代码：

型号：

class Playlist(models.Model):
    title = models.CharField(max_length=40, null=True)
    description = models.CharField(max_length=500, null=True)
    author = models.ForeignKey(User, default=None, on_delete=models.CASCADE)
    created_at = models.DateTimeField(auto_now_add=True)
    updated_at = models.DateTimeField(auto_now=True)
    miniature = models.ImageField(upload_to='images/playlist', default="defaults/default.png", validators=[validate_miniature_file_extension])
    tracks = models.ManyToManyField(Track)

    def __str__(self):
        return self.title

url：

path('<slug:author>', PlaylistDetail.as_view(), name='playlist'),

视图：

class PlaylistDetail(DetailView):
    model = Playlist
    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['now'] = timezone.now()
        return context

我想它的原因是同一用户创建了多个播放列表，并且它必须获得用户&&标题。有什么建议吗？

Answer 1

问题在于，您在网址中使用<slug:author>

path('<slug:author>', PlaylistDetail.as_view(), name='playlist'),

默认情况下，它会寻找slug。

尝试使用以下方法更新视图：

class PlaylistDetail(DetailView):
    model = Playlist
    slug_url_kwarg = 'author' # <----
    def get_context_data(self, **kwargs):
        # . . .

简单的Django DetailView不起作用，如何传递将2个参数传递给DetailView

1 个答案: