我想存储另一个表中的数据（id，profile_image，标题） （我只是下载用于上传图片的代码） 问题是当我要保存数据时，processForm.php始终为我提供的Session ID零值，即我当前的ID为“ 1”。 我是这里的新手。
（login.php）
<?php
// Initialize the session
session_start();
// Check if the user is already logged in, if yes then redirect him to
welcome page
if(isset($_SESSION["loggedin"]) && $_SESSION["loggedin"] === true){
header("location: welcome.php");
exit;
}
// Include config file
require_once "config.php";
// Define variables and initialize with empty values
$username = $password = "";
$username_err = $password_err = "";
// Processing form data when form is submitted
if($_SERVER["REQUEST_METHOD"] == "POST"){
// Check if username is empty
if(empty(trim($_POST["username"]))){
$username_err = "Please enter username.";
} else{
$username = trim($_POST["username"]);
}
// Check if password is empty
if(empty(trim($_POST["password"]))){
$password_err = "Please enter your password.";
} else{
$password = trim($_POST["password"]);
}
// Validate credentials
if(empty($username_err) && empty($password_err)){
// Prepare a select statement
$sql = "SELECT id, username, password FROM users WHERE username = ?";
if($stmt = mysqli_prepare($link, $sql)){
// Bind variables to the prepared statement as parameters
mysqli_stmt_bind_param($stmt, "s", $param_username);
// Set parameters
$param_username = $username;
// Attempt to execute the prepared statement
if(mysqli_stmt_execute($stmt)){
// Store result
mysqli_stmt_store_result($stmt);
// Check if username exists, if yes then verify password
if(mysqli_stmt_num_rows($stmt) == 1){
// Bind result variables
mysqli_stmt_bind_result($stmt, $id, $username, $hashed_password);
if(mysqli_stmt_fetch($stmt)){
if(password_verify($password, $hashed_password)){
// Password is correct, so start a new session
session_start();
// Store data in session variables
$_SESSION["loggedin"] = true;
$_SESSION["id"] = $id;
$_SESSION["username"] = $username;
// Redirect user to welcome page
header("location: welcome.php");
} else{
// Display an error message if password is not valid
$password_err = "The password you entered was not valid.";
}
}
} else{
// Display an error message if username doesn't exist
$username_err = "No account found with that username.";
}
} else{
echo "Oops! Something went wrong. Please try again later.";
}
}
// Close statement
mysqli_stmt_close($stmt);
}
// Close connection
mysqli_close($link);
}
?>
<!DOCTYPE html>
<html lang="en">
<link rel="stylesheet" type="text/css" href="style.css">
<link rel="icon" href="logo2.png" type="image">
<head>
<title>Fox - Log In | Sign Up</title>
<meta charset="windows-1252">
</head>
<body>
<div class="header" id="myHeader" >
<img src="logo.png" alt="Fox Logo" width="5%" height="20%">
<div class="tooltip">
<img src="text.png" alt="Fox text" width="50%" height="15%" usemap="#foxlogo">
<span class="tooltiptext">Go To Fox Home</span>
</div>
<map name="foxlogo">
<area shape="rect" coords="0,0,133,126" href="login.php">
</map>
</div>
<div class="container">
<img class="img" src="bg2.jpg">
</div>
<div class="signup"><br><br><br><br><br>
<h1 style="text-align:center; font-size:12;">Log In</h1><br>
<form style="margin-left:25px; margin-top: -20px;" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<div class="form-group <?php echo (!empty($username_err)) ? 'has-error' : ''; ?>">
<p style="font-size: 14px; color: white;margin-left: 0px;width: 980px;">Username</p>
<input placeholder="Enter Username" type="text" name="username" class="form-control" value="<?php echo $username; ?>">
<br><span class="help-block"><?php echo $username_err; ?></span>
</div>
<div class="form-group <?php echo (!empty($password_err)) ? 'has-error' : ''; ?>">
<p style="font-size: 14px; color: white;margin-left: 0px;width: 980px;">Password</p>
<input placeholder="Enter Password" type="password" name="password" class="form-control" >
<span class="help-block"><?php echo $password_err; ?></span>
</div>
<div class="form-group">
<input style="margin-top:20px;" type="submit" class="button" value="Login">
</div>
<p2><a href="register.php" type="link">Sign up now</a></p2>
</form>
</div>
<div>
<img class="user" src="user.png">
</div>
<a type="link2" style="margin:30px; text-decoration: none;" href="#">Terms & Policies</a>
<a type="link2" style="text-decoration: none;" href="#">Help</a>
</div>
</body>
</html>
（welcome.php）
<?php
require_once "config.php";
// Initialize the session
session_start();
// Check if the user is logged in, if not then redirect him to login page
if(!isset($_SESSION["loggedin"]) || $_SESSION["loggedin"] !== true){
header("location: login.php");
exit;
}
?>
<!DOCTYPE html>
<html lang="en">
<link rel="stylesheet" type="text/css" href="home.css">
<link rel="icon" href="logo2.png" type="image">
<head>
<meta charset="UTF-8">
<title>Fox | Home</title>
<style type="text/css">
body{ font: 14px sans-serif; text-align: center; }
</style>
</head>
<body>
<br>
<a style="margin-left:90%;position: relative;" href="logout.php" name="signout" class="btn btn-danger">Sign Out</a>
<div style="margin-right:96%"class="tooltip">
<img style="margin-right: 96%;margin-top:0%;" src="logo.png" alt="Fox Logo" width="100%" usemap="#foxlogo">
<span class="tooltiptext">Go To Fox Home</span>
</div>
<map name="foxlogo">
<area shape="rect" coords="0,0,133,126" href="welcome.php">
</map>
<hr>
<div class="profile">
<div class="page-header">
<h1><b><?php echo htmlspecialchars($_SESSION["username"]); ?></b></h1>
<div class="container">
<img name="profile" class="image" src="images/placeholder.png" id="profileDisplay" style="display: block;width: 45%;margin: 10px auto;border-radius:50%;"><br>
<input type="file" name="profileImage" id="profileImage" style="display: none;">
<div class="overlay">
<div class="text"><br>
<a href="updateprofile.php" name="update" class="btn btn-danger">Update Profile</a><br><br><br>
<a href="#" name="View" class="btn btn-danger">View profile</a>
</div>
</div>
<?php
$con = mysqli_connect("localhost","root","","demo");
$q = mysqli_query($con,"SELECT * FROM users WHERE id ='{$_SESSION["id"]}'");
while($row = mysqli_fetch_assoc($q)){
echo $row['created_at'];
}
?>
</div>
<p>
<a href="reset-password.php" class="btn btn-warning">Reset Your Password</a><br><br><br>
</p>
</div>
</body>
</html>
（config.php）
<?php
/* Database credentials. Assuming you are running MySQL
server with default setting (user 'root' with no password) */
define('DB_SERVER', 'localhost');
define('DB_USERNAME', 'root');
define('DB_PASSWORD', '');
define('DB_NAME', 'demo');
/* Attempt to connect to MySQL database */
$link = mysqli_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD, DB_NAME);
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
?>
（updateprofile.php）
我尝试以这种形式回显我当前的id（1），这很好。但是在XAMPP php中保存ID时，我的管理员给了我零。 processForm为我的SESSION ID提供了零值
picture1:I try to echo my ID and its fine
Picture2:After I upload a picture. it gives me a zero value for ID
<?php
require_once "config.php";
include 'processForm.php';
// Initialize the session
session_start();
// Check if the user is logged in, if not then redirect him to login page
if(!isset($_SESSION["loggedin"]) || $_SESSION["loggedin"] !== true){
header("location: login.php");
exit;
}
?>
<!DOCTYPE html>
<html lang="en">
<link rel="stylesheet" type="text/css" href="home.css">
<link rel="icon" href="logo2.png" type="image">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous">
<head>
<meta charset="UTF-8">
<title>Fox | Home</title>
<style type="text/css">
body, html{ font: 14px sans-serif; text-align: center;height: 100%; width: 100%; }
</style>
</head>
<body>
<div style="margin-left:90%"class="tooltip">
<span class="tooltiptext">Go To Fox Home</span>
</div>
<map name="foxlogo">
<area shape="rect" coords="0,0,133,126" href="welcome.php">
</map>
</div>
<img style="margin-right: 90%; margin-top:2%;" src="logo.png" alt="Fox Logo" width="5%" usemap="#foxlogo">
<a style="margin-left:90%; margin-top:-5%; position: relative;" href="logout.php" name="signout" class="btn btn-danger">Sign Out</a>
<hr>
<div style="margin-left: 35%"class="container">
<div class="row">
<div class="col-4 offset-m-d4 form-div">
<form enctype="multipart/form-data" action="index.php" method="post" >
<h3 class="text-center">Upload Profile</h3>
<?php //echo htmlspecialchars($_SESSION["username"]);
echo " My id is {$_SESSION["id"]}"; ?>
<div class="form-group text-center">
<img src="images/placeholder.png" id="profileDisplay" onclick="triggerClick()" style="display: block;width: 60%;margin: 10px auto;border-radius:50%;">
<input type="file" name="profileImage" onchange="displayImage(this)" id="profileImage" style="display: none;">
</div>
<div clas="form-group">
<label for="caption">Caption</label>
<textarea name="caption" id="caption" class="form-control"></textarea>
</div>
<div class="form-group">
<br>
<button type="submit" name="save-user" class="btn btn-primary btn-block">Upload</button>
</div>
</form>
</div>
</div>
</div>
<br><br><br><br>
<script src="scripts.js"></script>
</body>
</body>
</html>
（processForm.php）
<?php
require_once "config.php";
//connect db
$conn = mysqli_connect('localhost','root','','demo');
if(isset($_POST['save-user'])){
$caption = $_POST['caption'];
$profileImageName =time() . '_' . $_FILES['profileImage']['name'];
$target = 'images/' . $profileImageName;
if(move_uploaded_file($_FILES['profileImage']['tmp_name'], $target)){
//* */
$sql = "INSERT INTO photos (id,profile_image,caption) VALUES ('{$_SESSION['id']}','$profileImageName','$caption')";
if (mysqli_query($conn, $sql)){
$msg="Image uploaded and saved to database";
$css_class = "alert-success";
}else{
$msg="Database error: Failed to save user";
$css_class = "alert-danger";
}
//
$msg="Image uploaded";
$css_class = "alert-success";
header("location: welcome.php");
}else{
$msg="Failed to upload";
$css_class = "alert-danger";
header("location: updateprofile.php");
}
}
答案 0 :(得分：0)
您可以在登录后添加$_SESSION变量的输出var_dump();，然后在mysql中将照片保存的同时添加另一个(processForm.php)并进行比较？我认为您的session_start ();也一开始就不见了……var s: String = "hello"