Question

我正在创建UIStackView，并在一个循环中创建一定数量的UILabel和UISwitch对，并将它们添加到UIStackView中。现在如何获得UISwitch的状态为 ON 或 OFF ？

？

 func addAnswrsToTheStack(using answers: [Answer]){
    createHorizontalStackView()
    horizontalStackView.addArrangedSubview(questionProgressView)

    var questionSwitch: UISwitch!

 for answer in answers {
    createHorizontalStackView()
    let label: UILabel = UILabel()
    label.numberOfLines = 0
    label.lineBreakMode = .byWordWrapping
    label.textAlignment = .left
    label.text = answer.text

    horizontalStackView.addArrangedSubview(label)

    questionSwitch = UISwitch()

    questionSwitch.isOn = false
    horizontalStackView.addArrangedSubview(questionSwitch)
    }

}

Answer 1

您可以通过调用UISwitch来获得isOn的值，方法与设置相同。您可以遍历stackView中的所有视图，使用

检查该视图是否为开关

for view in horizontalStackView.arrangedSubviews {
    if view is UISwitch {
      // check the value here
    }
}

Answer 2

您可以尝试

for (index,answer) in answers.enumerated() { 
  ....
  questionSwitch = UISwitch() 
  questionSwitch.tag = index
  questionSwitch.isOn = false
  questionSwitch.addTarget(self, action: #selector(switchChanged), for:.valueChanged)
}

@objc func switchChanged(_ mySwitch: UISwitch) {
    let value = mySwitch.isOn
    print(mySwitch.tag , value)
}

Answer 3

您不知道每个答案的开关状态，因为您仅创建了开关，但没有保存该关联。一种干净的方法是具有Answer和UISwitch的wrappertype。但是，让我们暂时不要这样做。您需要返回一个映射，告诉您哪个开关与哪个问题相关。
类型[Answer：UISwitch]将起作用，仅此而已。现在，您可以查找每个Switch及其状态以获得答案。

class OrderListView(SingleTableMixin,FilterView):
    table_class = OrderTable
    model = Order
    template_name='orders/orde_list.html'
    filterset_class = OrderFilter

    def get_context_data(self, **kwargs):
        context = super(OrderListView, self).get_context_data(**kwargs)
        ##filter the orders of the past 4 months.
        last_four_months=date.today() - timedelta(120)
        object_list=Order.objects.filter(order_created__gte=last_four_months,ays=1).order_by('-invoice_date')
        table=self.table_class(object_list)
        RequestConfig(self.request).configure(table)
        context['table'] = table
        #clear all fields
        has_filter = any(field in self.request.GET for field in set(self.filterset_class.get_fields()))
        context['has_filter'] = has_filter
        return context

如何在SWIFT中循环获取已创建和添加到stackView的开关的开关状态

3 个答案: