我正在尝试让for循环在其下运行5次代码迭代,但一旦运行一次,并且我尝试单击矩形,则代码将无响应。 我不明白为什么会这样,所以我正在寻求帮助。
def Reaction_game():
intro = True
while intro == True:
for event in pygame.event.get():
#Stops game when close is selected
if event.type == pygame.QUIT:
file=open('currentuser.txt', 'w')
file.close()
pygame.quit()
quit()
Reaction_times=[]
for x in range (5):
clicked = False
BackGround = Background("background1.png",[0,0])
screen.fill(white)
screen.blit(BackGround.image, BackGround.rect)
pygame.draw.rect(screen, black,(0,0,1000,55))
Font = pygame.font.SysFont('TitilliumWeb.ttf',72)
Label = Font.render("Get Ready:", 1, white)
screen.blit(Label, (380,0,325,75))
pygame.display.update()
time.sleep(2)
screen.blit(BackGround.image, BackGround.rect)
pygame.draw.rect(screen, black,(0,0,1000,55))
Font = pygame.font.SysFont('TitilliumWeb.ttf',72)
Label = Font.render("Go:", 1, white)
screen.blit(Label, (450,0,325,75))
pygame.display.update()
RectX = randrange(50,950)
RectY = randrange(60,513)
round_rect(screen,(RectX,RectY,75,40),(black),10,5,(white))
pygame.display.update()
TimeStart = time.time()
while clicked !=True:
mouse = pygame.mouse.get_pos()
if RectX+75 > mouse[0] > RectX and RectY+40 > mouse[1] > RectY:
if event.type == pygame.MOUSEBUTTONDOWN and event.button == 1:
TimeEnd = time.time()
ReactionTime = TimeEnd - TimeStart
Reaction_times.append(ReactionTime)
clicked = True
else:
pass
Reaction_game()
我希望代码可以运行5次此小反应时间游戏的迭代,但在无响应之前它甚至不会超过第一个循环。
答案 0 :(得分:0)
您必须在for event in pygame.event.get():
内使用while clicked
才能从系统获取新事件。否则,您在event.type
和even.button
中将具有相同的值。
即使pygame.mouse.get_pos()
也无法正常工作,因为它使用了pygame.event.get()
(或类似的文件)创建的数据
如果您有事件MOUSEBUTTONDOWN
,MOUSEBUTTONUP
,那么您在event.pos
中拥有鼠标位置,并且不需要pygame.mouse.get_pos()
while not clicked:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
if event.type == pygame.MOUSEBUTTONDOWN and event.button == 1:
if RectX+75 > event.pos[0] > RectX and RectY+40 > event.pos[1] > RectY:
TimeEnd = time.time()
ReactionTime = TimeEnd - TimeStart
Reaction_times.append(ReactionTime)
clicked = True
编辑:
您可以将矩形的位置和大小保留在pygame.Rect()
RectX = randrange(50,950)
RectY = randrange(60,513)
rect = pygame.Rect(RectX, RectY, 75, 40)
然后您可以使用rect
代替(RectX,RectY,75,40)
round_rect(screen, rect, black , 10, 5, white)
,您可以使用rect
来检查是否单击了矩形rect.collidepoint(event.pos)
if event.type == pygame.MOUSEBUTTONDOWN and event.button == 1:
if rect.collidepoint(event.pos):
TimeEnd = time.time()
ReactionTime = TimeEnd - TimeStart
Reaction_times.append(ReactionTime)
clicked = True
编辑:具有其他更改的有效示例-即我用pygame.time.wait()
代替time.sleep()
,用pygame.time.get_ticks()
代替time.time()
。两者都使用毫秒而不是秒。
import pygame
import random
# --- constants ---
WHITE = (255, 255, 255)
BLACK = ( 0, 0, 0)
# --- main ---
pygame.init()
screen = pygame.display.set_mode((1000, 600))
reaction_times= []
for x in range(5):
clicked = False
screen.fill(WHITE)
pygame.draw.rect(screen, BLACK, (0, 0, 1000, 55))
font = pygame.font.SysFont(None, 72)
label = font.render("Get Ready:", 1, WHITE)
screen.blit(label, (380, 0, 325, 75))
pygame.display.update()
pygame.time.wait(2000) # 2000ms = 2s
pygame.draw.rect(screen, BLACK, (0, 0, 1000, 55))
font = pygame.font.SysFont(None, 72)
label = font.render("Go:", 1, WHITE)
screen.blit(label, (450, 0, 325, 75))
pygame.display.update()
x = random.randrange(50, 950)
y = random.randrange(60, 513)
rect = pygame.Rect(x, y, 75, 40)
pygame.draw.rect(screen, BLACK, rect)
pygame.display.update()
time_start = pygame.time.get_ticks()
while not clicked:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
if event.type == pygame.MOUSEBUTTONDOWN and event.button == 1:
if rect.collidepoint(event.pos):
print('clicked')
time_end = pygame.time.get_ticks()
reaction_time = (time_end - time_start)/1000 # convert to seconds
reaction_times.append(reaction_time)
clicked = True
print(reaction_times)
pygame.quit()