Question

我将以下代码另存为send.php：

<?php
$to_email = "person@gmail.com";
$subject = $_POST['subject'];
$body = "Hi, This is test email send by PHP Script";
$headers = "From: Me@myWebsite.com";

if ( mail($to_email, $subject, $body, $headers)) {
    echo("Email successfully sent to $to_email...");
} else {
    echo("Email sending failed...");
}
?>

如果我导航到https://myWebsite.com/Stuff/send.php，电子邮件将发送并制作$subject = "something"

但是如果我将$subject设置为POST变量。当我在浏览器中写入此URL时，它不会发送主题（例如，电子邮件仍然发送，但主题现在为空）：

 https://myWebsite.com/Stuff/send.php?subject=notworking

我一直在为这个问题绞尽脑汁，并且已经挣扎了几个小时。有人知道吗？

Answer 1

如果要从URL参数中提取值，则需要使用{ "id": "78a07cea-be2b-499c-b82b-e4f510260484", "version": "1.0.0", "actors": [ { "id": "1234567", "type": "XXX", "role": "111" }, { "id": "7654321", "type": "YYY", "role": "222" } ], "payload": { "name":"", "number":"" } } 全局变量来获取这样的数据，

$_GET

Answer 2

要同时获得$_POST和$_GET，您可以使用$_REQUEST，两者都适用。

在您的代码中替换

$subject = $_GET['subject'];

使用

$subject = $_REQUEST['subject'];

如果某人直接在浏览器中点击了没有参数主题的URL，则可以阻止他们使用

if(!empty($_REQUEST['subject']))
{
  $to_email = "person@gmail.com";
  $subject = $_REQUEST['subject'];
  $body = "Hi, This is test email send by PHP Script";
  $headers = "From: Me@myWebsite.com";

  if ( mail($to_email, $subject, $body, $headers))
    echo("Email successfully sent to $to_email...");
  else
    echo("Email sending failed...");
}

Answer 3

尝试一下。

 <?php
    $to_email = "person@gmail.com";
    $subject = (isset($_GET['subject']) && (!empty($_GET['subject']))?$_GET['subject']:"No Subject";
    $body = "Hi, This is test email send by PHP Script";
    $headers = "From: Me@myWebsite.com";

    if ( mail($to_email, $subject, $body, $headers))
        echo("Email successfully sent to $to_email...");
    else
        echo("Email sending failed...");
?>

POST请求空白，为什么？

3 个答案: