Question

我遇到键盘错误：“ main”。我搜索了许多站点，但仍然找不到任何令人满意的答案来解决此错误。如果有人可以给我一些指导，我将不胜感激。提前致谢。

我尝试通过在站点建议的 init .py上添加一个函数来解决此问题。但是它仍然没有用。 https://forum.inductiveautomation.com/t/error-on-sys-modules/6431/2

代码：view.py

#special-deals-animation {
  position: relative;
  width: 100%;
  background-color: #fff;
  height:auto;
  overflow :hidden;
  margin: 20px 0;
}

#animation-container {
  width: 50%;
  margin: 2% 25%;
  display: none;
  text-align: center;
}

#special-deals-animation.active {
  border: 1px solid #f00;
  width: 100%;
  transition: left 0.15s ease 0.15s, height 0.5s ease 0.5s;
  animation-iteration-count: 1;
}

#special-deals-animation.inactive {
  width: 0;
  height: 0;
  transition: left 0.15s ease 0.5s, height 0.5s ease;
  animation-iteration-count: 1;
}

终端：

from django.shortcuts import render
import requests
from .models import City


def index(request):
    url = 'http://api.openweathermap.org/data/2.5/weather?q={}&units=imperial&appid=MYKey'
    cities = City.objects.all()  # return all the cities in the database
    city = 'Dhaka'
    # request the API data and convert the JSON to Python data types
    city_weather = requests.get(url.format(city)).json()

    weather_data = []

    for city in cities:

        # request the API data and convert the JSON to Python data types
        city_weather = requests.get(url.format(city)).json()

        weather_app = {
            'city': city,
            'temperature': city_weather['main']['temp'],
            'description': city_weather['weather'][0]['description'],
            'icon': city_weather['weather'][0]['icon']
        }

        # add the data for the current city into our list
        weather_data.append(weather_app)

    #context = {'weather' : weather_app}
    context = {'weather_data': weather_data}

    # returns the index.html template
    return render(request, 'weather_app/index.html')

Answer 1

您无需检查是否已找到特定城市的数据。您遍历数据库中的所有城市，并尝试获取每个城市的天气；但您不检查结果是否实际返回。您应该这样做：

for city in cities:
    response = requests.get(url.format(city))
    if response.status_code == 404:
        continue
    city_weather = response.json()

此外，您应该检查自己是否正确设置了网址格式。就目前而言，您是将City对象直接插入URL中-仅当您定义了仅返回城市名称的__str__方法时，此方法才有效。最好直接使用该名称：

response = requests.get(url.format(city.name))   # or whatever the name field is

Answer 2

我不确定。我有个建议。在制作city_weather之前，您可以检查weather_app数据（使用print（））以查看密钥'main'是否确实在city_weather中，也许密钥恰巧不在数据。

为什么会发生KeyError：'main'以及如何解决它

2 个答案: