Question

我有2个ComboBox。但是我需要根据combo_maker的值来更新combo_type。

我试图进行ComboSelected筛选，但失败了。

当combobox_maker时，我选择了任何值。 combobox_type没有变化。我尝试了一些代码更改，但一无所获。

from tkinter import *
from tkinter import ttk
import sqlite3
import tkinter as tk
from tkinter import messagebox
import configparser
import tkinter
import tkinter
import mysql.connector
from mysql.connector import Error

Product = Tk()
Product.title ('App - Add Product')
Product.geometry("800x600")
#CONNECT DB
def connect_db():
        config = configparser.ConfigParser()
        config.read('config.ini')
        return mysql.connector.connect(host = config['mysql']['host'],
                                        port = config['mysql']['port'],
                                        user = config['mysql']['database_user'],
                                        passwd = config['mysql']['database_password'],
                                        db = config['mysql']['database_name'])
#CONNECT DB

#COMBO MAKER
def combo_input_maker():#<--Populate combo_maker
    conn = connect_db()
    cursor = conn.cursor()
    cursor.execute("SELECT maker_name FROM makers")
    result=cursor.fetchall()
    return result
#COMBO MAKER

#COMBO TYPE
def combo_input_type():#<--Populate combo_type
    conn = connect_db()
    cursor = conn.cursor()
    some_name = combo_maker.get()#<--Query with value select from combo_maker
    cursor.execute("SELECT t1.type FROM maker_types t1 INNER JOIN makers t2 ON t1.maker_id = t2.id WHERE maker_name =%s", [some_name])
    result=cursor.fetchall()
    return result
#COMBO TYPE

combo_maker = ttk.Combobox(Product,state="readonly")
combo_maker['value'] = [item for result in combo_input_maker() for item in result if item]
combo_maker.current(0)
combo_maker.bind('<<ComboboxSelected>>', combo_input_type())#<--When ComboboxSelected in combo_maker, call def combo_input_type()
combo_maker.place(x=5, y=5, height = 25, width = 180)

combo_type = ttk.Combobox(Product,state="readonly")
combo_type['value'] = [item for result in combo_input_type() for item in result if item]
combo_type.current(0)
combo_type.place(x=200, y=5, height = 25, width = 180)

Product.mainloop()

combo_maker更改后，combo_type不变。

Answer 1

由于您要从数据库中提取数据，因此我无法运行您的代码，但是通常您可以为此创建dict。下面是一个简单的示例。

import tkinter as tk
from tkinter import ttk

root = tk.Tk()

dic = {"A": ["Apple","Orange"],
       "B": ["Pineapple","Banana"],
       "C": ["Watermelon","Kiwi"]}

def on_select(event):
    b_box["values"] = dic[a_box.get()] #modify 2nd combobox directly
    b_box.current(0)

a_box = ttk.Combobox(root,value=[k for k in dic],state="readonly")
a_box.pack()
b_box = ttk.Combobox(root,state="readonly")
b_box.pack()

a_box.bind("<<ComboboxSelected>>",on_select)

root.mainloop()

Answer 2

主要问题是：

您错误地初始化了askdirectory;
您传递的结果 combo_maker代替的函数引用 comb_input_type()中的comb_input_type。

下面是根据您的代码修改的代码：

combo_make.bind(...)

根据组合框1填充组合框2

2 个答案: