我有一个彩票程序,可以进行投注并随机生成数字。当用户的总奖金达到$ 5000时,该用户可以选择兑现$ 5000并使用剩余余额继续循环。如果选择不套现,用户也将能够结束循环。如何根据用户输入继续循环?如果用户输入是,则循环将继续,但是我不确定如何执行此操作。有人可以帮忙吗?如果应该继续循环,则由于兑现而从用户的总胜利中删除了$ 5000,剩余的余额将用于游戏。
我曾尝试在主循环中的多个位置放置供用户输入的if语句,但用户预算一直在增加,它不会减去$ 5000。
java.util.Scanner
while (budget > 0) {
lottery = (int) (Math.random() * 100);
guess = (int) (Math.random() * 100);
budget -= 1; // budget = budget-1;
// Get digits from lottery
int lotteryDigit1 = lottery / 10;
int lotteryDigit2 = lottery % 10;
// Get digits from guess
int guessDigit1 = guess / 10;
int guessDigit2 = guess % 10;
System.out.println("The lottery number is " + lottery);
System.out.println("The computer picked number is " + guess);
// Check the guess
if (guess == lottery) {
System.out.println("Exact match: you win $10,000");
totalWin += 1000;
} else if (guessDigit2 == lotteryDigit1 && guessDigit1 == lotteryDigit2) {
System.out.println("Match all digits: you win $3,000");
totalWin += 300;
} else if (guessDigit1 == lotteryDigit1 || guessDigit1 == lotteryDigit2 || guessDigit2 == lotteryDigit1
|| guessDigit2 == lotteryDigit2) {
System.out.println("Match one digit: you win $1,000");
totalWin += 100;
} else
System.out.println("Sorry, no match");
budget += totalWin;
totalWin=0;
if (budget > initBudget)
if ((budget-initBudget) >= 5000) {
System.out.println("You have reached the goal of 5000, we can go home!");
System.out.println("Enter 1 if you would like to cash out and use remaining balance to play and 0 if you would like to stop");
int decison = input.nextInt();
if (decison==1){budget=budget-5000;
System.out.println("Budget After play " + budget);
continue;
}break;
}
System.out.println("Budget After play " + budget);
}
所以在我的代码中,我有了循环
System.out.println("Enter 1 if you would like to cash out and use remaining balance to play and 0 if you would like to stop");
int decison = input.nextInt();
if (decison==1){budget=budget-5000;
System.out.println("Budget After play " + budget);
continue;
}break;
}
此循环应接收用户输入,然后从总赢额中减去5000,并使用剩余的预算继续进行游戏..但它只是在增加。不知道为什么如果我有-5000,它会增加。
(如果可能,请帮助我将答案改为是/否,而不是输入1)
答案 0 :(得分:2)
我假设您正在使用java.util.Scanner
。这是答案;
System.out.println("Enter yes if you would like to cash out and use remaining balance to play and no if you " +
"would like to stop");
String decison = input.nextLine();
if ("yes".equals(decison))
{
budget = budget - 5000;
System.out.println("Budget After play " + budget);
continue;
}
break; // break the statement.
答案 1 :(得分:1)
ErçinAkçay解释了如何将输入从int更改为String。
我看了看您的代码,并使用它制作了一个可运行的main方法,它可以按您期望的那样工作。可能需要从初始预算中扣除5k的事实令人困惑吗?
if ((budget - initBudget) >= 5000)
这是我用来检查代码的整个类,如果有帮助的话:
import java.util.Scanner;
public class Test {
private static int budget;
private static int lottery;
private static int guess;
private static int totalWin;
private static int initBudget = 4500;
public static void main(String[] args) throws InterruptedException {
Scanner input = new Scanner(System.in);
budget = initBudget;
while (budget > 0) {
lottery = (int) (Math.random() * 100);
guess = (int) (Math.random() * 100);
budget -= 1; // budget = budget-1;
// Get digits from lottery
int lotteryDigit1 = lottery / 10;
int lotteryDigit2 = lottery % 10;
// Get digits from guess
int guessDigit1 = guess / 10;
int guessDigit2 = guess % 10;
System.out.println("The lottery number is " + lottery);
System.out.println("The computer picked number is " + guess);
// Check the guess
if (guess == lottery) {
System.out.println("Exact match: you win $10,000");
totalWin += 1000;
} else if (guessDigit2 == lotteryDigit1 && guessDigit1 == lotteryDigit2) {
System.out.println("Match all digits: you win $3,000");
totalWin += 300;
} else if (guessDigit1 == lotteryDigit1 || guessDigit1 == lotteryDigit2 || guessDigit2 == lotteryDigit1
|| guessDigit2 == lotteryDigit2) {
System.out.println("Match one digit: you win $1,000");
totalWin += 100;
} else {
System.out.println("Sorry, no match");
}
budget += totalWin;
totalWin = 0;
if (budget > initBudget) {
if ((budget - initBudget) >= 5000) {
System.out.println("You have reached the goal of 5000, we can go home!");
System.out.println(
"Enter 1 if you would like to cash out and use remaining balance to play and 0 if you "
+ "would like to stop");
int decison = input.nextInt();
if (decison == 1) {
budget = budget - 5000;
System.out.println("Budget After play " + budget);
continue;
}
break;
}
}
System.out.println("Budget After play " + budget);
}
}
}
答案 2 :(得分:0)
您可以这样更改代码:
System.out.println("Enter yes if you would like to cash out and use remaining balance to play and no if you would like to stop");
String decision = input.next();
if ("Yes".equalsIgnoreCase(decision)) { // Cashing Out
budget = budget - 5000;
System.out.println("Budget After play " + budget);
continue;
}
break; // breaking the loop (if user enters anything other than yes)
在这里,我使用了String
(将用户的响应存储为一个单词)。如果他输入Yes
,yes
或YES
(忽略大小写,则认为用户要兑现),循环不会中断。