Question

我正在呼叫一个Web服务，该服务给了我Json Response。这是代码

URL url = new URL(strUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
...
//get response text
BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream(),"UTF-8"));           
StringBuffer response = new StringBuffer();
while ((respText = br.readLine()) != null) {                
    response.append(respText);
}
br.close(); 
retValue = response.toString();

问题是响应如下所示

"{\u000d\u000a  \"groups\": [\u000d\u000a    {\u000d\u000a      \"signingGroupId\": \"323793\",\u000d\u000a      \"groupName\": \"1440 Signing Group 1\",\u000d\u000a      \"groupType\": \"sharedSigningGroup\",\u000d\u000a      \"created\": \"3\/27\/2019 6:08:34 AM\",\u000d\u000a      \"createdBy\": \"ABC Software\",\u000d\u000a      \"modified\": \"4\/1\/2019 6:40:45 AM\",\u000d\u000a      \"modifiedBy\": \"Corner O'Brien\"\u000d\u000a    },\u000d\u000a    {\u000d\u000a      \"signingGroupId\": \"323794\",\u000d\u000a      \"groupName\": \"1440 Another Group\",\u000d\u000a      \"groupType\": \"sharedSigningGroup\",\u000d\u000a      \"created\": \"3\/27\/2019 6:14:52 AM\",\u000d\u000a      \"createdBy\": \"XYZ Software\",\u000d\u000a      \"modified\": \"3\/27\/2019 6:16:37 AM\",\u000d\u000a      \"modifiedBy\": \"XYZ Software\"\u000d\u000a    }\u000d\u000a  ]\u000d\u000a}"

我想从上述回复中做出这样的休养

"{"groups":[{"signingGroupId": "323793","groupName": "1440 Signing Group 1","groupType": "sharedSigningGroup","created": "3/27/2019 6:08:34 AM","createdBy": "ABC Software","modified": "4/1/2019 6:40:45 AM","modifiedBy": "John O'Brien"},{"signingGroupId": "323794","groupName": "1440 Another Group","groupType": "sharedSigningGroup","created": "3/27/2019 6:14:52 AM","createdBy": "ABC Software","modified": "3/27/2019 6:16:37 AM","modifiedBy": "ABC Software"}]}"

那是在那之后删除所有的\u000d\u000a和spaces。但不要从任何Json属性中删除空间。

我尝试过

retValue = retValue.replace("\\u000d\\u000a", "");
retValue = retValue.replace("\\", "");

这给了我

"{  "groups": [    {      "signingGroupId": "323793",      "groupName": "1440 Signing Group 1",      "groupType": "sharedSigningGroup",      "created": "3/27/2019 6:08:34 AM",      "createdBy": "ABC Software",      "modified": "4/1/2019 6:40:45 AM",      "modifiedBy": "John O'Brien"    },    {      "signingGroupId": "323794",      "groupName": "1440 Another Group",      "groupType": "sharedSigningGroup",      "created": "3/27/2019 6:14:52 AM",      "createdBy": "XYZ Software",      "modified": "3/27/2019 6:16:37 AM",      "modifiedBy": "XYZ Software"    }  ]}"

但是仍然有空格。现在，如果我使用

String replcaedNewLineAndSpaces = retValue.replaceAll("[ \t]+", "");

此行存在问题，因为它还会从“ Json属性”中删除空格。

"{"groups":[{"signingGroupId":"323793","groupName":"1440SigningGroup1","groupType":"sharedSigningGroup","created":"3/27/20196:08:34AM","createdBy":"ABCSoftware","modified":"4/1/20196:40:45AM","modifiedBy":"JohnO'Brien"},{"signingGroupId":"323794","groupName":"1440AnotherGroup","groupType":"sharedSigningGroup","created":"3/27/20196:14:52AM","createdBy":"XYZSoftware","modified":"3/27/20196:16:37AM","modifiedBy":"XYZSoftware"}]}"

请参阅groupName，它是"groupName": "1440 Signing Group 1"。现在变成 1440SigningGroup1。其他属性也是如此。

仍然存在吗？它将Json String保持原样，但在其后删除\u000d\u000a和spaces。因此，最终的响应变为

"{"groups":[{"signingGroupId": "323793","groupName": "1440 Signing Group 1","groupType": "sharedSigningGroup","created": "3/27/2019 6:08:34 AM","createdBy": "ABC Software","modified": "4/1/2019 6:40:45 AM","modifiedBy": "John O'Brien"},{"signingGroupId": "323794","groupName": "1440 Another Group","groupType": "sharedSigningGroup","created": "3/27/2019 6:14:52 AM","createdBy": "ABC Software","modified": "3/27/2019 6:16:37 AM","modifiedBy": "ABC Software"}]}"

谢谢

Answer 1

如评论中所述，创建一个POJO类并解析JSON是最佳且安全的。（我认为最常见的库是GSon library）

但是，如果您坚持要删除空格，请使用简单的正则表达式进行操作：

retValue.replaceAll("\\\\u000d\\\\u000a\\s*", "")

这将替换所有以\ u000d \ u000a开头的字符串，后跟0个无限制的空格。

从json响应中删除unicode字符串和空格

1 个答案: