处理json响应可观察到的迅速

时间:2019-05-02 15:09:59

标签: swift rx-swift swifty-json codable moya

我有一个使用SwiftyJSON并可以正常工作的应用程序。但是,现在我想扩展项目并重构代码,但是由于我现在切换到Codable时遇到了一些问题,我需要能够从任何路径而不是硬编码路径映射JSON。目前我的jsonResponse看起来像这样

/// handle the network response and map to JSON
    /// - returns: Observable<JSON>
    func handleResponseMapJSON() -> Observable<Result<JSON, ORMError>> {

        return self.map { representor in

            guard let response = representor as? Moya.Response else {
                return .failure(ORMError.ORMNoRepresentor)
            }

            guard ((200...299) ~= response.statusCode) else {
                return .failure(ORMError.ORMNotSuccessfulHTTP)
            }

            guard let json = JSON.init(rawValue: response.data),
                json != JSON.null,
                let code = json["code"].int else {
                    return .failure(ORMError.ORMParseJSONError)
            }

            guard code == BizStatus.BizSuccess.rawValue else {
                let message: String = {
                    let json = JSON.init(data: response.data)
                    guard let msg = json["status"].string else { return "" }
                    return msg
                }()
                log(message, .error)
                return .failure(ORMError.ORMBizError(resultCode: "\(code)", resultMsg: message))
            }

            return .success(json["result"])

        }
    }

如何消除硬编码的json[""]值的传递。感谢您的帮助

2 个答案:

答案 0 :(得分:0)

我建议您尝试这样的事情:

protocol ResponseType: Codable {
    associatedtype ResultType
    var status: String { get }
    var code: Int { get }
    var result: ResultType { get }
}

func handleResponseMap<T, U>(for type: U.Type) -> (Any) -> Result<T, ORMError> where U: ResponseType, T == U.ResultType {
    return { representor in
        guard let response = representor as? Moya.Response else {
            return .failure(.ORMNoRepresentor)
        }
        guard ((200...299) ~= response.statusCode) else {
            return .failure(.ORMNotSuccessfulHTTP)
        }
        return Result {
            try JSONDecoder().decode(U.self, from: response.data)
            }
            .mapError { _ in ORMError.ORMParseJSONError }
            .flatMap { (response) -> Result<T, ORMError> in
                guard response.code == BizStatus.BizSuccess.rawValue else {
                    log(response.status, .error)
                    return Result.failure(ORMError.ORMBizError(resultCode: "\(response.code)", resultMsg: response.status))
                }
                return Result.success(response.result)
        }
    }
}

然后,您可以直接映射到您的可编码类型:

let result = self.map(handleResponseMap(for: MyResponse.self))

在上面,结果将最终为Observable<Result<ResultType, ORMError>>

答案 1 :(得分:0)

我想对PrimitiveSequenceType进行扩展,以将其视为Single

import Foundation
import RxSwift
import Moya

 public extension PrimitiveSequenceType where TraitType == SingleTrait, ElementType == Response {
    func map<T>(_ type: T.Type, using decoder: JSONDecoder? = nil) -> PrimitiveSequence<TraitType, T> where T: Decodable {
        return self.map { data -> T in
            let decoder = decoder ?? JSONDecoder()
            return try decoder.decode(type, from: data.data)
        }
    }
}

,您可以像这样简单地使用它:

return  PokeAPIEndPoints.shared.provider.rx
        .request(.specieDetails(id: specieId))
        .filterSuccessfulStatusCodes()
        .map(SpecieDetails.self)