范围可以是5到10 到目前为止,这是我所做的,但仍然没有做到我想要的
<script>
function checkpattern(elem)
{
var textbox = document.getElementById("textbox");
if(textbox.value.length<=10 && textbox.value.length>=5)
{
alert("5 to 10");
}
else
{
if(!elem.value.match('^'+elem.getAttribute('pattern')+'$'))
{
alert('Accepts digits only');
}
}
}
</script>
<input type = "text" name = "amt" maxlength = "10" pattern = [0-9] onchange = checkpattern(this) placeholder="Enter Amount" onfocus="this.placeholder = ''" onblur="this.placeholder = 'Enter Amount '" required="">
答案 0 :(得分:1)
如果您使用minlength
,除非它的字符数超过5个,否则它将不允许您提交
<input type = "text" name = "amt" minlength="5" maxlength = "10" pattern = [0-9] onchange = checkpattern(this) placeholder="Enter Amount" onfocus="this.placeholder = ''" onblur="this.placeholder = 'Enter Amount '" required="">
如果要将其设置为数量(数字),则可以使用min
和max
:
<input type = "number" name = "amt" min="5" max = "10" pattern = [0-9] onchange = checkpattern(this) placeholder="Enter Amount" onfocus="this.placeholder = ''" onblur="this.placeholder = 'Enter Amount '" required="">
答案 1 :(得分:0)
您的代码中有很多问题,如果其他地方不对,并且您也没有正确传递输入值
<script>
function checkpattern(elem)
{
if(elem<=10 && elem>=5)
{
alert("5 to 10");
}
if(!elem.match(/^\d+$/))
{
alert('Accepts digits only');
}
}
</script>
<input type = "text" name = "amt" maxlength = "10" pattern = [0-9] onchange = checkpattern(this.value) placeholder="Enter Amount" onfocus="this.placeholder = ''" onblur="this.placeholder = 'Enter Amount '" required="">